在django中创建我自己的上下文处理器 [英] creating my own context processor in django

问题描述

我已经到了一个点，我需要传递某些变量到我的所有观点（主要是自定义认证类型变量）。

我被告知写自己的上下文处理器是最好的方法，但是我有一些问题。

我的设置文件看起来像这样

  TEMPLATE_CONTEXT_PROCESSORS =（
django.contrib.auth.context_processors.auth，
django.core.context_processors.debug，
 django.core.context_processors.i18n，
django.core.context_processors.media，
django.contrib.messages.context_processors.messages，
sandbox.context_processors.say_hello ，
）
  

如你所见，我有一个名为'context_processors'的模块，

看起来像

  def say_hello（request）：
 return {
'say_hello'：你好，
} 
  

我是否可以假设我现在可以在我的意见中执行以下操作？

  {{say_hello}} 
  

现在，这在我的模板中无效。

我的看法看起来像

  from django.shortcuts import render_to_response 
 
 def test（request）：
 return render_to_response（test.html）
  pre> 
 
解决方案
您编写的上下文处理器应该可以工作。您是否认为问题是您的看法。
 
 
 
您是否肯定您的视图是使用 RequestContext 呈现？
 
 
 
例如：
  def test_view（request）：
 return render_to_response（'template.html'）
  
上面的视图不会使用 TEMPLATE_CONTEXT_PROCESSORS 。确保您提供 RequestContext ，如下所示：
  def test_view请求）：
返回render_to_response（'template.html'，context_instance = RequestContext（请求））
  
 
I have come to a point where I need to pass certain variables to all of my views (mostly custom authentication type variables).

I was told writing my own context processor was the best way to do this, but I am having some issues.

My settings file looks like this
TEMPLATE_CONTEXT_PROCESSORS = (
    "django.contrib.auth.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "django.contrib.messages.context_processors.messages",
    "sandbox.context_processors.say_hello", 
)
As you can see, I have a module called 'context_processors' and a function within that called 'say_hello'.

Which looks like
def say_hello(request):
        return {
            'say_hello':"Hello",
        }
Am I right to assume I can now do the following within my views?
{{ say_hello }}
Right now, this renders to nothing in my template.

My view looks like
from django.shortcuts import render_to_response

def test(request):
        return render_to_response("test.html")

解决方案
The context processor you have written should work.   The problem is in your view.

Are you positive that your view is being rendered with RequestContext?

For example:
def test_view(request):
    return render_to_response('template.html')
The view above will not use the context processors listed in TEMPLATE_CONTEXT_PROCESSORS.  Make sure you are supplying a RequestContext like so:
def test_view(request):
    return render_to_response('template.html', context_instance=RequestContext(request))


                        
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