使用通配符从子进程调用rm不会删除文件 [英] Calling rm from subprocess using wildcards does not remove the files

问题描述

我正在尝试构建一个功能，将从我的项目根目录中删除所有以'prepend'开头的文件。这是我到目前为止

I'm trying to build a function that will remove all the files that start with 'prepend' from the root of my project. Here's what I have so far

def cleanup(prepend):
    prepend = str(prepend)
    PROJECT_ROOT = os.path.abspath(os.path.dirname(__file__))
    end = "%s*" % prepend
    cmd = 'rm'
    args = "%s/%s" % (PROJECT_ROOT, end)
    print "full cmd = %s %s" %(cmd, args)
    try:
        p = Popen([cmd, args],  stdin=PIPE, stdout=PIPE, stderr=PIPE, close_fds=True).communicate()[0]
        print "p", p
    except Exception as e:
        print str(e)

我没有任何运气 - 似乎没有做任何事情。你有什么想法我可能做错了吗？谢谢！

I'm not having any luck -- it doesn't seem to be doing anything. Do you have any ideas what I might be doing wrong? Thank you!

推荐答案

问题是你传递两个参数到 subprocess.Popen ： rm 和路径，如 / home / user / t * （如果前缀为 T ）。 Popen 然后将尝试删除一个名为的文件，这样：t后面加上一个星号。

The problem is that you are passing two arguments to subprocess.Popen: rm and a path, such as /home/user/t* (if prefix is t). Popen then will try to remove a file named exactly this way: t followed by an asterisk at the end.

如果要使用通配符 Popen ，则应将 shell 参数作为真。但是，在这种情况下，命令应该是字符串，而不是参数列表：

If you want to use Popen with the wildcard, you should pass the shell parameter as True. In this case, however, the command should be a string, not a list of arguments:

Popen("%s %s" % (cmd, args), shell=True, stdin=PIPE, stdout=PIPE, stderr=PIPE, close_fds=True)

（否则，参数列表将被提供给新的shell，而不是命令）

另一个更安全，更高效的解决方案是使用 glob 模块：

Another solution, safer and more efficient, is to use the glob module:

import glob
files = glob.glob(prepend+"*")
args = [cmd] + files
Popen(args,  stdin=PIPE, stdout=PIPE, stderr=PIPE)

然而，总而言之，我同意levon解决方案是更为清晰的解决方案。在这种情况下， glob 也是答案：

All in all, however, I agree that levon solution is the saner one. In this case, glob is the answer too:

files = glob.glob(prepend+"*")
for file in files:
    os.remove(file)

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