[上载"一个来自django shell的文件 [英] "Upload" a file from django shell

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本文介绍了[上载"一个来自django shell的文件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要从一个excel文件和一个带有图像的文件夹中导入一些数据,Excel中的每一行描述每个条目,并在文件夹中列出文件名(与该条目有关的照片)。

I need to import some data from a excel file and a folder with images, every row in the excel describes every entry and have a list of filenames in the folder (photos related to the entry).

我已经完成了一个脚本,它创建数据库中的每个条目,并通过django shell保存它,但我不知道如何实例化一个InMemoryUploadedFile,以保存它与模型。

I've done a script which creates every entry in the database and saves it trough the django shell, but i have no idea how to instantiate a InMemoryUploadedFile for save it with the model.

在django 1.0中,我有这个小班让我做我​​需要的,但是在django 1.1中有变化,它不再起作用了。

In django 1.0 I had this small class which allowed me to do what i need, but with changes in django 1.1 it's not working any more.

class ImportFile(file):
    def __init__(self, *args, **kwargs):
        super(ImportFile, self).__init__(*args, **kwargs)
        self._file = self
        self.size = os.path.getsize(self.name)

    def __len__(self):
        return self.size

    def chunks(self, chunk_size=None):
        self._file.seek(0)
        yield self.read()

我正在使用此类代码加载图像并使用模型实例保存。

I was using this class with this piece of code to load images and saving them with the model instance.

for photo in photos:
    f = ImportFile(os.path.join(IMPORT_DIR, 'fotos', photo), 'r')
    p = Photo(name=f.name, image=f, parent=supply.supply_ptr)
    name = str(uuid1()) + os.path.splitext(f.name)[1]
    p.image.save(name, f)
    p.save()

问题是,如何从python中的文件创建InMemoryUploadedFile或TemporaryUploadedFile? ,或任何其他可以在这种情况下工作的东西。

The question is, how do I create a InMemoryUploadedFile or TemporaryUploadedFile from a file in python?, or any other thing that could work in this context.

推荐答案

最后我找到了答案。 b

Finally I found the answer.

from django.core.files import File

f = File(open(os.path.join(IMPORT_DIR, 'fotos', photo), 'r'))
p = Photo(name=f.name, image=f, parent=supply.supply_ptr)
name = str(uuid1()) + os.path.splitext(f.name)[1]
p.image.save(name, f)
p.save()

这篇关于[上载"一个来自django shell的文件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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