在django模板中获取模板名称 [英] Getting the template name in django template
问题描述
为了进行调试,我想在所有模板中都有一个变量,其中包含正在呈现的模板的路径。例如,如果视图呈现模板/ account / logout.html,我希望{{template_name}}包含字符串templates / account / logout.html。
For debugging purposes, I would like to have a variable in all my templates holding the path of the template being rendered. For example, if a view renders templates/account/logout.html I would like {{ template_name }} to contain the string templates/account/logout.html.
我不想去改变任何观点(特别是因为我正在重用很多应用程序),所以去的方式似乎是一个内省的内容处理器。这个问题是要内省的。
I don't want to go and change any views (specially because I'm reusing a lot of apps), so the way to go seems to be a context processor that introspects something. The question is what to introspect.
或者也许这是内置的,我不知道吗?
Or maybe this is built in and I don't know about it?
推荐答案
简单的方法
下载并使用 django调试工具栏。
不太简单的方法
将 Template.render
替换为 django.test.utils.instrumented_test_render
,收听 django.test.signals.template_rendered
信号,并将模板的名称添加到上下文中。请注意,您的设置文件中的 TEMPLATE_DEBUG
必须为true,否则将无法获取名称。
Replace Template.render
with django.test.utils.instrumented_test_render
, listen for the django.test.signals.template_rendered
signal, and add the name of the template to the context. Note that TEMPLATE_DEBUG
must be true in your settings file or there will be no origin from which to get the name.
if settings.DEBUG and settings.TEMPLATE_DEBUG
from django.test.utils import instrumented_test_render
from django.test.signals import template_rendered
def add_template_name_to_context(self, sender, **kwargs)
template = kwargs['template']
if template.origin and template.origin.name
kwargs['context']['template_name'] = template.origin.name
Template.render = instrumented_test_render
template_rendered.connect(add_template_name_to_context)
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