Django请求发布json [英] Django request Post json

问题描述

我尝试测试一个视图，我收到来自IPad的json请求，格式为：

I try to test a view, I receive a json request from the IPad, the format is:

req = {"custom_decks": [
        {
            "deck_name": "deck_test",
            "updates_last_applied": "1406217357",
            "created_date": 1406217380,
            "slide_section_ids": [
                1
            ],
            "deck_id": 1
        }
          ],
    "custom_decks_to_delete": []
}

我在jsonlint中检查过，并通过了

I checked this in jsonlint and it passed.

我通过以下方式发布要求：

I post the req via:

response = self.client.post('/library/api/6.0/user/'+ uuid +
'/store_custom_dec/',content_type='application/json', data=req) 

视图返回creation_success：false

The view return "creation_success": false

问题是post方法在视图中找不到关键字custom_decks。

The problem is the post method in view doesn't find the key custom_decks.

QueryDict: {u'{"custom_decks": [{"deck_id": 1, "slide_section_ids": [1], 
"created_date":1406217380, "deck_name": "deck_test"}], 
"custom_decks_to_delete": []}': [u'']}>

问题是Post方法在视图中找不到关键的custom_decks。
因为它是用一个键将我的dict转换成QueryDict。

The problem is the post method in view doesn't find the key custom_decks. Because it is converting my dict to QueryDict with one key.

我感谢所有的帮助。

谢谢

推荐答案

您正在发布与格式编码数据不同的JSON。您需要获取 request.body 的值，并对其进行反序列化：

You're posting JSON, which is not the same as form-encoded data. You need to get the value of request.body and deserialize it:

data = json.loads(request.body)
custom_decks = data['custom_decks']

这篇关于Django请求发布json的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！