具有以下参数的url的Django {%url%}:url(r'^ foo /< parameter> / $',include(some.urls)) [英] Django {% url %} when urls with parameters like: url(r'^foo/<parameter>/$', include(some.urls))
问题描述
我没有找到任何解决方案,如何使用以下配置(使用Django1.3)获取模板中的网址:
urls.py
urlpatterns = patterns('',
url(r'^ / foo /(?P< ;参数> \d +)/ $',include('bar.urls'),name ='foo-url'),
)
包含url-conf:
bar.urls.py
urlpatterns = patterns('',
(r'^ / bar / $','bar.views.index'),
url(r'^ / bar /(?P< parameter2> \d +)/ $','bar.views.detail',name ='bar-url'),
)
bar.views.py
$ detail $($)
obj1 = Foo.objects.get(id = parameter)
obj2 = Bar.objects.get( id = parameter2)
现在我尝试使用以下模板获取网址:
{%url bar-url parameter = 1参数2 = 2%}
我希望得到: / bar / 1 / foo / 2 /
在这种情况下可以使用{%url%}吗?
是的,你可以这样得到你的网址: -
{%url'bar -url'1 2%}
但请注意,您的网址配置实际上应该是这样的: / p>
urls.py
urlpatterns = pattern('',
url(r'^ / foo /(?P< parameter> \d +)/,include('bar.urls'))
)
bar.urls.py
urlpatterns = patterns('',
(r'^ / bar / $,'bar.views.index'),
url(r'^ / bar / (?P< parameter2> \d +)/ $,'bar.views.detail',name ='bar-url'),
)
没有 foo-url
,除非你特别地映射: -
urls.py
urlpatterns = patterns('',
url(r'^ / foo /(?P< parameter> \d +)/ $,'another.views.foo ',name ='foo'),
url(r'^ / foo /(?P< parameter> \d +)/,include('bar.urls')),
)
请注意, $
表示正则表达式的结尾。
i don't find any solution, how to get the url in template with the following configuration (using Django1.3):
urls.py
urlpatterns = patterns('',
url(r'^/foo/(?P<parameter>\d+)/$', include('bar.urls'), name='foo-url'),
)
Included url-conf:
bar.urls.py
urlpatterns = patterns('',
(r'^/bar/$', 'bar.views.index'),
url(r'^/bar/(?P<parameter2>\d+)/$', 'bar.views.detail', name='bar-url'),
)
bar.views.py
def detail(request, parameter, parameter2):
obj1 = Foo.objects.get(id=parameter)
obj2 = Bar.objects.get(id=parameter2)
Now I try to get the url in template with:
{% url bar-url parameter=1 parameter2=2 %}
I expect to get: /bar/1/foo/2/
Is it posible to use in this case the {% url %}?
Yes, you can get your url like this:-
{% url 'bar-url' 1 2 %}
But note that your url configuration should actually be like this:-
urls.py
urlpatterns = patterns('',
url(r'^/foo/(?P<parameter>\d+)/, include('bar.urls')),
)
bar.urls.py
urlpatterns = patterns('',
(r'^/bar/$, 'bar.views.index'),
url(r'^/bar/(?P<parameter2>\d+)/$, 'bar.views.detail', name='bar-url'),
)
There is no foo-url
unless you specifically map:-
urls.py
urlpatterns = patterns('',
url(r'^/foo/(?P<parameter>\d+)/$, 'another.views.foo', name='foo'),
url(r'^/foo/(?P<parameter>\d+)/, include('bar.urls')),
)
Note that $
means the end of the regular expression.
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