django模板中的逗号分隔列表 [英] Comma separated lists in django templates

问题描述

如果 fruit 是列表 ['apples'，'oranges'，'pears'] ，

有没有快速的方式使用django模板标签来生成苹果，橘子和梨？

我知道使用循环和 {％if counter.last％} 语句来执行此操作并不困难，但是由于我将重复使用这一点，我想我将要必须学习如何编写自定义标签过滤器，如果已经完成，我不想重新发明。

作为我试图放弃牛津逗号（即退回苹果，橘子和梨）是

解决方案

我建议一个自定义django模板过滤器而不是自定义标签 - 过滤器更加简单（在适当的情况下，像这里）。 {{fruits |加入：，}} 看起来像我想要的目的...使用自定义 joinby filter：

  def joinby（value，arg）：
 return arg.join（value）
  

您所看到的只是简单本身！

If fruits is the list ['apples', 'oranges', 'pears'],

is there a quick way using django template tags to produce "apples, oranges, and pears"?

I know it's not difficult to do this using a loop and {% if counter.last %} statements, but because I'm going to use this repeatedly I think I'm going to have to learn how to write custom tags filters, and I don't want to reinvent the wheel if it's already been done.

As an extension, my attempts to drop the Oxford Comma (ie return "apples, oranges and pears") are even messier.

解决方案

I would suggest a custom django templating filter rather than a custom tag -- filter is handier and simpler (where appropriate, like here). {{ fruits | joinby:", " }} looks like what I'd want to have for the purpose... with a custom joinby filter:

def joinby(value, arg):
    return arg.join(value)

which as you see is simplicity itself!

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