Django捕捉所有网址，而不会打破APPEND_SLASH [英] Django catch-all URL without breaking APPEND_SLASH

问题描述

我在我的urls.py中有一个条目，作为一个catch-all，它在数据库中找到一个适当的页面时加载一个简单的视图。这种方法的问题是，URL解算程序将永远不会失败，这意味着APPEND_SLASH功能不会启动 - 我需要。

我宁愿不必须诉诸于向静态页面网址添加前缀，以阻止它成为全部的。我知道平板电脑，它使用404钩子而不是urls.py中的条目，我有希望避免使用它，但我猜这个问题可能正是这样一个原因。

任何方式解决这个问题，还是应该放入并使用平板？

解决方案

确保您的全部URL模式在结尾处有斜杠，并且该模式是URLconf中的最后一个。如果catch-all模式不以斜线结尾，那么它将匹配流水网址，然后中间件尝试附加斜杠。

例如，使用 r'^。* / $'而不是 r'^。*'作为您的最后一个模式。

要做同样的事情，但是将URL作为命名参数传递给视图，请使用 r'^（？P< url>。*）/ $' code>。

I have an entry in my urls.py that acts as a catch-all which loads a simple view if it finds an appropriate page in the database. The problem with this approach is that the URL solver will then never fail, meaning that the APPEND_SLASH functionality won't kick in - which I need.

I'd rather not have to resort to adding a prefix to the static page URLs to stop it being a catch-all. I do know about flatpages, which uses a 404 hook rather than an entry in urls.py, and I had kinda hoped to avoid having to use it, but I guess this problem might be exactly the kind of reason why one would use it.

Any way round this problem or should I just give in and use flatpages?

解决方案

Make sure that your catch-all URL pattern has a slash at the end, and that the pattern is the last in your URLconf. If the catch-all pattern doesn't end with a slash, then it will match stray URLs before the middleware tries appending a slash.

For example, use r'^.*/$' instead of r'^.*' as your last pattern.

To do the same, but pass the url to the view as a named argument, use r'^(?P<url>.*)/$'.

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