Django：使用Post（）方法的ListView？ [英] Django: ListView with post() method?

问题描述

我正在尝试在基于Django类的视图中处理两种形式。该网站包含一个名为表单的表单（基于 GET ），用于缩小ListView的列表结果和第二个表单 status_form （根据 POST ）。

因为ListView返回一个项目列表。 表单允许用户限制选择，并且 status_forms 允许用户通过模态窗体标记不正确的项目（因此需要在同一个模板）。

我的麻烦是 ListView 不附带方法 post ，但是 FormView 。我的类列表继承自两个类，但是当我执行该类时，我收到错误消息：

属性错误：'List'对象没有属性'status_form'

如何更改我的实现以允许第二个表单通过发布方法？

  class List（PaginationMixin，ListView，FormMixin）：
 model = ListModel 
 context_object_name ='list_objects'
 template_name ='pages / list.html'
 paginate_by = 10＃可能每页的项目
 
 def get（self，request，* args，** kwargs）：
 self.form = ListSearchForm（self.request.GET或者None，）
 return super（List，self）.get（request，* args，** kwargs）
 
 def post（self，request，* args，** kwargs） 
 self.status_form = StatusForm（self.request.POST或None）
如果self.status_fo rm.is_valid（）：
 ... 
 else：
 return super（List，self）.post（request，* args，** kwargs）
 
 def get_queryset（self）：
＃定义查询
 ... 
＃完成后，传递给object_list 
 return object_list 
 
 def get_context_data（self ，** kwargs）
 context = super（List，self）.get_context_data（** kwargs）
 context.update（** kwargs）
上下文['form'] = self。形式
上下文['status_form'] = self.status_form＃Django正在抱怨status_form不存在，因为post方法不执行结果
 return context 
  

解决方案

 ＃Django正在抱怨status_form不存在，
＃结果，因为post方法不执行
上下文['status_form'] = self.status_form 
  

因为您没有定义 self .status_from 首先。
您已在 get_context_data 中定义，并可从那里访问。

您可以访问您的对象

  context = self.get_context_data（*）$ {code> get_context_data  * kwargs）
 status_form = context ['status_form'] 
  

还要考虑你可以定义您的 status_form 直接在发布方法本身，而不从 self 或 get_context_data 。

重新设计您的视图以分开单独视图中的每个表单处理，然后用每个其他

重新设计视图：

简而言之，让每个视图执行一项工作。您可以创建一个视图来处理您的 status_form ，并将其命名为 StatusFormProcessView 然后在您的列表视图返回它的发布方法

  class List（ListView）; 
 def post（self，request，* args，** kwargs）：
 return StatusFormView.as_view（request）＃什么你需要传递给你表单处理视图
  

这只是一个例子，需要更多的工作才能真实。

另一个例子;在我的网站索引页面上，我有一个搜索表单。当用户 POST 或 GET 搜索表单时，搜索的处理不存在于我的 IndexView ，而是在单独的视图中处理整个表单的东西，如果表单应该在 GET 方法上处理，我将覆盖 get（）方法，如果表单应该在 POST 上处理，我将覆盖 post（）方法将 search_form 数据发送到负责处理 search_form 的视图。 p>

评论回复

status_form = context ['status_form']

不应该是

  context ['status_form' ] = status_form 
  

在创建后？

你想从上下文中获得 status_form ，所以你需要

  status_form = context ['status_form'] 
  

无论如何，您的表单数据可在 self.request.POST

I am trying to process two forms in a Django class based view. The site contains a form called form (based on GET) for narrowing the list results of the ListView and the second form status_form (based on POST).

Both forms are required since the ListView returns a list of items. Form lets the user restrict the choices and status_forms lets the user flag incorrect items via a modal form (therefore it needs to be in the same template).

My trouble is that ListView does not come with the method post, however FormView does. My class List inherits from both classes, but when I execute the class I get the error message:

Attribute Error: 'List' object has no attribute 'status_form'

How should I change my implementation to allow the second form been processed via the post method?

class List(PaginationMixin, ListView, FormMixin):
    model = ListModel
    context_object_name = 'list_objects'
    template_name = 'pages/list.html'
    paginate_by = 10 #how may items per page

    def get(self, request, *args, **kwargs):
        self.form = ListSearchForm(self.request.GET or None,)
        return super(List, self).get(request, *args, **kwargs)

    def post(self, request, *args, **kwargs):
        self.status_form = StatusForm(self.request.POST or None)
        if self.status_form.is_valid():
            ...
        else:
            return super(List, self).post(request, *args, **kwargs)

    def get_queryset(self):
        # define the queryset
        ...
        # when done, pass to object_list
        return object_list

    def get_context_data(self, **kwargs):
        context = super(List, self).get_context_data(**kwargs)
        context.update(**kwargs)
        context['form'] = self.form
        context['status_form'] = self.status_form # Django is complaining that status_form is not existing, result since the post method is not executed
        return context

解决方案

# Django is complaining that status_form does not exist,
# result since the post method is not executed
context['status_form'] = self.status_form

Because you didn't define self.status_from in the first place. You have defined in get_context_data, And it's accessible from there.

You can access you object from get_context_data in your post method;

context = self.get_context_data(**kwargs)
status_form = context['status_form']

Also consider that you can define your status_form directly in post method itself without getting it from self or get_context_data.

Redesign you views to separate each Form processing in separate Views then tight them with each-other.

Views redesign:

In nutshell, let each view to do one job. You can create a View just for processing your status_form and name it like StatusFormProcessView then on your List view return it on its post method

class List(ListView);
    def post(self, request, *args, **kwargs):
        return StatusFormView.as_view(request) # What ever you need be pass to you form processing view

This is just an example of it, need more work to be real.

For another example; On my website index page I have a search form. when user POST or GET the search form, The processing of searching doesn't exist in my IndexView, instead I handle the whole form stuff in separate view, If form should process on GET method, I'll override get() method, If form should process on POST, I'll override post() method to send search_form data to the view that is responsible for handling of processing the search_form.

Comments response

status_form = context['status_form']

shouldn't it be

context['status_form'] = status_form

after I created it ?

You want to get status_form from context, So you need to

status_form = context['status_form']

Anyway, your form data are available on self.request.POST

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