Django的。 Python社会认证。在管道末端创建轮廓 [英] Django. Python social auth. create profiles at the end of pipeline

问题描述

我想在auth流水线末尾添加一个函数，该函数用于检查该用户是否有Profiles表，如果不存在，将创建一个表。
Profiles模型是一个表，其中存储有关用户的一些额外信息：

I want to add a function at the end of the auth pipeline, the function is meant to check if there is a "Profiles" table for that user, if there isn't it will create a table. The Profiles model is a table where I store some extra information about the user:

class Profiles(models.Model):
    user = models.OneToOneField(User, unique=True, null=True)
    description = models.CharField(max_length=250, blank=True, null=True)
    points = models.SmallIntegerField(default=0)
    posts_number = models.SmallIntegerField(default=0)

每个用户必须具有个人档案表。所以，我在管道末端添加了一个函数：

Each user must have a Profiles table. So, I added a function at the end of the pipeline:

SOCIAL_AUTH_PIPELINE = (
    'social.pipeline.social_auth.social_details',
    'social.pipeline.social_auth.social_uid',
    'social.pipeline.social_auth.auth_allowed',
    'social.pipeline.social_auth.social_user',
    'social.pipeline.user.get_username',
    'social.pipeline.user.create_user',
    'social.pipeline.social_auth.associate_user',
    'social.pipeline.social_auth.load_extra_data',
    'social.pipeline.user.user_details',
    'app.utils.create_profile'  #Custom pipeline
)

#utils.py 
def create_profile(strategy, details, response, user, *args, **kwargs):
    username = kwargs['details']['username']
    user_object = User.objects.get(username=username)
    if Profiles.ojects.filter(user=user_object).exists():
        pass
    else:
        new_profile = Profiles(user=user_object)
        new_profile.save()
    return kwargs

我收到错误：

 KeyError at /complete/facebook/
 'details'
 ...
 utils.py in create_profile
 username = kwargs['details']['username']

我是蟒蛇社交认证的新手，看起来我缺少一些明显的东西。任何帮助将不胜感激。

I'm new to python social auth, and it looks that I'm missing something obvious. Any help will be appreciated.

推荐答案

好的，所以我会回答我自己的问题，以防万一它对未来。我不是专家，但这里是：

Ok so I'll answer my own question just in case it is useful for someone in the future. I'm no expert but here it is:

我在追踪这个教程，因为他是

I was following this tutorial, and becouse he does

 email = kwargs['details']['email']

我以为我可以做

username = kwargs['details']['username']

但它没有起作用，它给了我一个KeyError。

But it didn't work, it gave my a KeyError.

然后我试过：

username = details['username']

它的工作。但是我有一个新的问题，详细信息的用户名是u'Firstname Lastname，当我试图获取User对象

And it worked. But I had a new problem, the username from the details dict was something like u'Firstname Lastname' and when I tried to get the User object

user_object = User.objects.get(username=username)

没有找到，因为用户模型中的用户名是u'FirstnameLastname'（没有空格）。

It was not found, becouse the username in the User model was u'FirstnameLastname' (without the space).

最后我再次阅读了文档，我发现我可以简单地使用用户对象直接，它被传递给函数为user：

Finally I read the docs again and I found out that I could simply use the user object directly, it gets passed to the function as "user":

def create_profile(strategy, details, response, user, *args, **kwargs):

    if Profiles.objects.filter(usuario=user).exists():
        pass
    else:
        new_profile = Profiles(user=user)
        new_profile.save()

    return kwargs

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