如何在Django-admin中呈现自定义嵌套复选框视图？ [英] How can I render a custom nested checkbox tree view in Django-admin?

问题描述

我有一个错误模型，映射到类别。类别可以拥有其他类别。

I have a bugs model which is mapped to categories. Categories can own other categories.

class Bug( models.Model ):
    categories = models.ManyToManyField('Category')
    name = models.CharField( max_length=100 )
    slug = models.SlugField(unique=True)
    summary = models.TextField()
    summary_markdown = models.TextField(editable=False, blank=True)
    date_added = models.DateTimeField(auto_now_add=True)
    browser = models.ManyToManyField( Browser )
    poster = models.ForeignKey(User)

class Category ( models.Model ):
    name = models.CharField( max_length=100 )
    slug = models.SlugField(unique=True)
    parent = models.ForeignKey( 'self', null=True, blank=True, related_name='children' )

    class Meta:
    ordering = ['name']
    verbose_name_plural = 'Categories'

    def __unicode__(self):
    return self.name

我已经在使用django-mptt了前端视图来渲染类别。我想知道如何修改管理员视图，这样当我去创建一个新的错误，而不是以非层次顺序的类别的下拉列表，我得到一个层次顺序与复选框，而不是一个下拉列表。

I am already using django-mptt on the front end view to render categories. I'm wondering how I can modify the admin view so that when I go to create a new bug, instead of a dropdown of categories in non-hierarchial order I get a hierarchial order with checkboxes instead of a dropdown.

某些东西：

(checkbox) CSS
   (checkbox) Display
       (checkbox) Inline-block
       (checkbox) Block
   (checkbox) Float
   (checkbox) Height
       (checkbox) Min-height

推荐答案

我有一个类似的问题，但是使用一个布局有点不同。您需要创建一个自定义窗口小部件来显示类别。
这是我如何做我的：

I had a similar problem, but used a layout a little bit diffrent. You need to create a custom widget for displaying the categories. This is how I did it mine:

from itertools import chain

from django import forms
from django.db import models
from django.forms.widgets import CheckboxSelectMultiple
from django.utils.encoding import force_unicode
from django.utils.html import conditional_escape
from django.utils.safestring import mark_safe

class CustomCheckboxSelectMultiple(forms.CheckboxSelectMultiple):

    items_per_row = 1 # Number of items per row      

    def render(self, name, value, attrs=None, choices=()):
        if value is None: value = []
        has_id = attrs and 'id' in attrs
        final_attrs = self.build_attrs(attrs, name=name)
        output = ['<table><tr>']
        # Normalize to strings
        str_values = set([force_unicode(v) for v in value])
        for i, (option_value, option_label) in enumerate(chain(self.choices, choices)):
            # If an ID attribute was given, add a numeric index as a suffix,
            # so that the checkboxes don't all have the same ID attribute.
            if has_id:
                final_attrs = dict(final_attrs, id='%s_%s' % (attrs['id'], i))
                label_for = ' for="%s"' % final_attrs['id']
            else:
                label_for = ''           
                cb = forms.CheckboxInput(final_attrs, check_test=lambda value: value in str_values)
                option_value = force_unicode(option_value)
                rendered_cb = cb.render(name, option_value)
                option_label = conditional_escape(force_unicode(option_label))
                if i != 0 and i % self.items_per_row == 0:
                    output.append('</tr><tr>')
                #Here you need to put you layout logic for display the checkboxes 
                if self.choices[i][1].parent_id is None:
                    output.append('<td nowrap><label%s>%s</label></td>' % (label_for, option_label))
                else:
                    output.append('<td nowrap><label%s>%s %s</label></td>' % (label_for, rendered_cb, option_label))

        output.append('</tr></table>')       
        return mark_safe('\n'.join(output))

在models.py中我有：

In the models.py I have:

class MyModelForm(ModelForm):
    my_model_types = forms.MultipleChoiceField(label='My model types', widget = CustomCheckboxSelectMultiple, required=True)

    class Meta:
        model = MyModel                     

    def __init__(self, *args, **kwargs):
        super(self.__class__, self).__init__(*args, **kwargs)
        tree = Tree()
        tree.build_tree(reasons=MyModelType.objects.all())
        list = tree.as_list()    
        CHOICES = [(rt.pk, rt) for rt in list]             
        self.fields['reason_types'].choices = CHOICES

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