尝试显示从用户发布的链接中提取的图像 [英] trying to display the image that got extracted from the user posted link
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问题描述
Media.py
import json import urllib2 from urllib2 import请求从goose import Goose
def get_content（url）：
此函数旨在返回内容来自url
：param url：获取内容的URL
：return：来自url
的响应
req = urllib2.Request（url，headers = {'User -Agent'：Magic Browser}）
response = urllib2.Request.urlopen（req）.read（）
return response
def extract（url ）
url = get_content（url）
g = Goose（）
article = g.extract（url = url）
resposne = {'image'：article.top_image.src
return json.dumps（resposne）
view.py
class PostCreateView（CreateView）：
model = Post
form_class = PostForm
模板_name ='main / add_post.html'
def form_valid（self，form）：
self.object = form.save（commit = False）
＃任何手动设置这里
self.object.moderator = self.request.user
url = self.request.GET.get（'url'）
image = extract（url）
self。 object.save（）
return HttpResponseRedirect（reverse（'post'，args = [self.object.slug]））
@method_decorator（login_required）
def dispatch（self ，request，* args，** kwargs）：
return super（PostCreateView，self）.dispatch（request，* args，** kwargs）
def index ）
category = Category.objects.all（）
try：
sort = request.GET [sort]。strip（）
sort_method = SortMethods [sort]
page = request.GET [page]。strip（）
除了KeyError：
sort_method = SortMethods.score
page = 1
如果sort_method == SortMethods.date：
thread_list = Post.objects.order_by（ - pub_date）
else：
thread_list = Post.objects.all（）
thread_list = sorted（thread_list，key = lambda x：x.get_score（），reverse = True）
paginator = Paginator（thread_list，30）
try：
posts = paginator.page（page）
except PageNotAnInteger：
posts = paginator.page（1）
除了EmptyPage：
posts = paginator.page（paginator.num_pages）
context = {
posts：posts，
pages： paginator.page_range，
sort：sort_method.name，
categories：categories，
}
return render（request，main / index.html ，上下文）
Models.py
class Post（models.Model）：
category = models.ForeignKey（Category）
pub_date = models.DateTimeField（auto_now_add = True）
title = models.CharField（max_length = 100）
content = FroalaField（）
url = models.URLField（max_length = 250，blank = True，null = True）
moderator = models.ForeignKey（User）
rank_score = models.FloatField（default = 1）
views = models.IntegerField（default = 0）
image = models.ImageField（upload_to = images，blank = True，null = True）
slug = models.CharField（max_length = 100，unique = True）
objects = models.Manager（）
forms.py
class PostForm（forms.ModelForm）：
title = forms.CharField（max_length = 128，help_text =plz enter）
url = forms.URLField（max_length = 200，
help_text =请输入页面的URL，required = False）
v iews = forms.IntegerField（widget = forms.HiddenInput（），initial = 0）
content = forms.CharField（widget = FroalaEditor）
class Meta：
model = Post
exclude = ['pub_date'，'moderator'，'rank_score'，'image'，'slug']
解决方案
我没有看到你的models.py文件。所以我会这样做：
-
确保你在你类的models.py中有一个列
img = models.FileField（upload_to ='static / your_directory /'，null = True）
没有null = TrueDjango无法进行迁移。
-
提交Django后，将该图像放入上述目录。
-
在设置上下文数据后，在模板中渲染图像：
< img src =/ {{ your_object .img}}> ！不要忘记SLASH !!!
这是一个没有AJAX的设置。请阅读下面的评论，了解更多信息，thx。
This is what I'm trying to do. Let user post url, the url is submitted and extract main image from the link user posted. Display that image. I;m at a point the image got extracted as the user posted link(thank you for fixing the error) now I'm simply trying to display the image
Media.py
import json import urllib2 from urllib2 import Request from goose import Goose
def get_content(url):
"""This function is intended to return content from url.
:param url: URL to get content
:return: The response from url
"""
req = urllib2.Request(url, headers={'User-Agent': "Magic Browser"})
response = urllib2.Request.urlopen(req).read()
return response
def extract(url):
url = get_content(url)
g = Goose()
article = g.extract(url=url)
resposne = {'image':article.top_image.src}
return json.dumps(resposne)
views.py
class PostCreateView(CreateView):
model = Post
form_class = PostForm
template_name = 'main/add_post.html'
def form_valid(self, form):
self.object = form.save(commit=False)
# any manual settings go here
self.object.moderator = self.request.user
url = self.request.GET.get('url')
image = extract(url)
self.object.save()
return HttpResponseRedirect(reverse('post', args=[self.object.slug]))
@method_decorator(login_required)
def dispatch(self, request, *args, **kwargs):
return super(PostCreateView, self).dispatch(request, *args, **kwargs)
def index(request):
categories = Category.objects.all()
try:
sort = request.GET["sort"].strip()
sort_method = SortMethods[sort]
page = request.GET["page"].strip()
except KeyError:
sort_method = SortMethods.score
page = 1
if sort_method == SortMethods.date:
thread_list = Post.objects.order_by("-pub_date")
else:
thread_list = Post.objects.all()
thread_list = sorted(thread_list, key=lambda x: x.get_score(), reverse=True)
paginator = Paginator(thread_list, 30)
try:
posts = paginator.page(page)
except PageNotAnInteger:
posts = paginator.page(1)
except EmptyPage:
posts = paginator.page(paginator.num_pages)
context = {
"posts": posts,
"pages": paginator.page_range,
"sort": sort_method.name,
"categories":categories,
}
return render(request, "main/index.html", context)
Models.py
class Post(models.Model):
category = models.ForeignKey(Category)
pub_date = models.DateTimeField(auto_now_add = True)
title = models.CharField(max_length = 100)
content = FroalaField()
url = models.URLField(max_length=250, blank=True, null=True)
moderator = models.ForeignKey(User)
rank_score = models.FloatField(default= 1)
views = models.IntegerField(default=0)
image = models.ImageField(upload_to="images",blank=True, null=True)
slug = models.CharField(max_length=100, unique=True)
objects = models.Manager()
forms.py
class PostForm(forms.ModelForm):
title = forms.CharField(max_length=128, help_text="plz enter")
url = forms.URLField(max_length=200,
help_text="Please enter the URL of the page.", required=False)
views = forms.IntegerField(widget=forms.HiddenInput(), initial=0)
content = forms.CharField(widget=FroalaEditor)
class Meta:
model = Post
exclude = ['pub_date', 'moderator', 'rank_score', 'image','slug']
解决方案
I don't see your models.py file. So I would do this:
Make sure, that you have in your models.py in your class a "column" e.g.
img = models.FileField(upload_to='static/your_directory/', null=True)
Without "null=True" Django cannot make migrations.
After submitting Django will place that image into mentioned directory.
Render image in your template after setting context data:
<img src="/{{ your_object.img }}"> !!! do NOT forget the SLASH !!!
This is a setup without AJAX. Please read comments below for futher information, thx.
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