旋转精灵的AABB？ [英] AABB of rotated sprite?

问题描述

说我有一个精灵。它的轴对齐包围盒（AABB）是很容易找到，因为我知道的宽度和高度。说我旋转45度，我不认为AABB将大到足以覆盖它，所以我需要一个新的AABB。我该如何计算旋转矩形的边框？ （给定的一个中心点，角度，以及它的宽度和高度）。

Say I have a sprite. Its axis-aligned bounding box (AABB) is easy to find since I know the width and height. Say I rotate it 45 degrees, I don't think the AABB would be big enough to cover it, so I need a new AABB. How can I calculate the bounding rectangle of a rotated rectangle? (given a center point, an angle, and its width and height).

需要注意的是OpenGL的不旋转，所以我没有访问到顶点的信息。

Note that OpenGL does the rotation so I do not have access to the vertex information.

我想要做的就是这样的AABB我可以做2D扑杀进行渲染。

What I'm trying to do is get AABBs so I can do 2D culling for rendering.

有没有可能找到满足任意角度的AABB的贪婪的方法是什么？

Is there possibly a greedy way of finding the AABB that satisfies any angle?

感谢

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