获取django Url模板标签来返回有用的东西：抛出反向错误 [英] getting django Url template tag to return something useful:throws reverse error

问题描述

尝试使用Django {％url％} 模板标签，并保持失败。
视图在sitename / transfers / views.py中定义（其中transfer是django应用程序名称）：

  def description_ListView（requesst，** kwargs）：
 
 template_name ='transfers / description.html'
 
o = get_list_or_404（Transfer，description = kwargs ['description']）
 #print（'o：'，o）
 context_object_name =transfer_name_list
返回render_to_response（template_name，{context_object_name：o，'description'：kwargs ['description']}）
  

（是的，我知道这段代码有点奇怪，努力使这个更通用，中间有这个令人讨厌的问题）

，并且URL被映射到transfer / urls.py

  url（r'^ description /（？P< description> [\w] +）/ $'，
'transfers.views.description_ListView'，
 name =' description_url'）
  

并在标签中：
{％urldescription_urlblabla％}
也尝试过：
{％url .Description_ListViewdescription =blabla％}

错误信息：

 异常类型：NoReverseMatch 
异常值：
反向''description_url'与参数'（u'blabla'，）'和关键字参数'{}'未找到。 
  

或者当我尝试使用作为somename 语法和调用如下：`{{somename}}。刚刚失败，没有任何东西。

我也尝试从视图导入Description_ListView并直接使用它，没有帮助。

此外，在各种SO问题中，遵循关于此主题的许多答案的建议，我更改为视图中的双引号，并恢复使用url名称而不是视图，但没有帮助。 p>

我很乐意为此提供任何帮助

解决方案

不要以为你需要报价。尝试：

  {％url description_urlblabla％} 
  

请参阅 https://docs.djangoproject.com/en/dev/topics/http/urls/#naming-url-patterns

trying to use the Django {%url %} template tag and keep failing. the view is defined in sitename/transfers/views.py (where transfers is the django app name):

def description_ListView(requesst,**kwargs):

    template_name = 'transfers/description.html'

    o = get_list_or_404(Transfer, description =kwargs['description'])
    #print ('o:',o)
    context_object_name = "transfer_name_list" 
    return render_to_response(template_name,{context_object_name:o,'description':kwargs['description']})

(yes, I DO know that this code is a little strange. working on making this more generic and caught in the middle with this annoying problem)

and the url is mapped in transfers/urls.py

url(r'^description/(?P<description>[\w ]+)/$',
                           'transfers.views.description_ListView',
                           name = 'description_url')

and in the tag: {% url "description_url" "blabla" %} also tried: {% url "transfers.views.Description_ListView" description = "blabla" %}

the error message:

Exception Type: NoReverseMatch
Exception Value:    
Reverse for '"description_url"' with arguments '(u'blabla',)' and keyword arguments '{}' not found.

or when i Tried using the as somename syntax and calling it like this: `{{somename}}. just failed silently and didn't produce anything.

where I also tried importing the Description_ListView from the views and using it directly, didn't help.

Also, following the advice of numerous answers on this subject in various SO questions I changed to double quotes around the view, and reverted to using the url name instead of view but neither helped.

I'll be glad for any help with this

解决方案

I don't think you need quotes. Try:

{% url description_url "blabla" %}

See https://docs.djangoproject.com/en/dev/topics/http/urls/#naming-url-patterns

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