Django：检查多个选项，而不是固定的选择 [英] Django: Check multiple choices with not fixed choices

问题描述

我是Django的新手，我正尝试用复选框创建一个多重选择。问题是，我发现所有的例子都有固定的选择，在表单中指定，我不需要。

I am new to Django, and I am trying to create a multiple selection with checkboxes. The problem is that all of the examples that I found have fixed choices that are specified in the form, and I don't need that.

更具体地说，一个简单的汽车经销商应用程序的模型：

More concretely, let this be a model for a simple car dealership app:

class CarBrand(models.Model):
    name = model.CharField()

class CarModel(models.Model):
    name = model.CharField()
    brand = model.ForeignKey(CarBrand)

我的目标是当我进入奥迪的页面时，我可以选择A3，A4，A5，但是当我进入宝马的页面时，我获取选项M3，M4，M5。点击提交后，应发送所有选择的车型。

My goal is when I enter the page for Audi, I get options A3, A4, A5, but when I enter the page for BMW, I get options M3, M4, M5. After clicking the submit it should send all the car models that were selected.

推荐答案

给表单一个 __init __ 方法，获取CarBrand作为参数，然后根据以下条件设置查询器进行选择：

Give the form an __init__ method that gets a CarBrand as a parameter, then set the queryset to choose from based on that:

class CarForm(forms.Form):
    def __init__(self, car_brand, *args, **kwargs):
        self.fields['cars'] = forms.ModelMultipleChoiceField(
            queryset=CarModel.objects.filter(brand=car_brand),
            widget=forms.CheckboxSelectMultiple)
        super(CarForm, self).__init__(*args, **kwargs)

在您的视图中，首先获取相关的CarBrand实例，创建具有 CarForm（car_brand ，request.POST）等。

Now in your view get the relevant CarBrand instance for the page first, the create the form with CarForm(car_brand, request.POST) etc.

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