将JSON数据导入Django View / Template [英] Importing JSON data into Django View/Template
本文介绍了将JSON数据导入Django View / Template的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的json:
[{target stocks.shared(last:4204.0),datapoints:[[4379.0,1389225600],[4204.0,1389312000]]}]
这是我的视图文件看起来像
def get_context_data(self,** kwargs )
context = super(IndexView,self).get_context_data(** kwargs)
上下文['stocks'] = JSON PULL
返回上下文
我尝试过这个,它没有工作,因为json打开并不意味着外部拉。
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解决方案
您可以使用 urllib.urlopen
获取外部JSON数据,像这样:
从urllib import urlopen
def get_context_data(self,** kwargs) :
context = super(IndexView,self).get_context_data(** kwargs)
my_stock_url ='http://mystockpage.org/stocks/'
上下文['stocks'] = json.loads(urlopen(my_stock_url).read())
上下文['last_stock'] = stock [0] ['target']。split()[2] .strip(')'
return context
So im working on a project and im using json data from a graphite graph and im trying to import it into the django views.py file and then get the value I want in the template. The import will be happening from a remote URL not from directly on the server itself.
here is my json:
[{"target": "stocks.shared (last: 4204.0)", "datapoints": [[4379.0, 1389225600], [4204.0, 1389312000]]}]
This is what my views file will look like
def get_context_data(self, **kwargs):
context = super(IndexView, self).get_context_data(**kwargs)
context['stocks'] = JSON PULL
return context
I tried this and It did not work mostly because json open is not meant to pull externally.
json_data=open('URL')
context['shared'] = json.load(json_data)
解决方案
You can simply use urllib.urlopen
to get external JSON data, like this:
from urllib import urlopen
def get_context_data(self, **kwargs):
context = super(IndexView, self).get_context_data(**kwargs)
my_stock_url = 'http://mystockpage.org/stocks/'
context['stocks'] = json.loads(urlopen(my_stock_url).read())
context['last_stock'] = stocks[0]['target'].split()[2].strip(')')
return context
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