想从另一个视图django打印出一个项目列表 [英] Want to print out a list of items from another view django
问题描述
我有一个显示列表项的视图。
I have a view which displays a list items.
def edit_order(request, order_no):
try:
status_list = models.Status.objects.all()
order = models.Order.objects.get(pk = order_no)
if order.is_storage:
items = models.StorageItem.objects.filter(orderstoragelist__order__pk = order.pk)
else:
items = models.StorageItem.objects.filter(orderservicelist__order__pk = order.pk)
except:
return HttpResponseNotFound()
我想将这些项目列表放在另一个视图中。不幸的是,这被证明是比较棘手的,然后我想。
I want to put these list of item in another view. Unfortunately this is proving to be trickier then I thought.
@login_required
def client_items(request, client_id = 0):
client = None
items = None
try:
client = models.Client.objects.get(pk = client_id)
items = client.storageitem_set.all()
item_list = models.StorageItem.objects.filter(orderstoragelist__order__pk = order.pk)
except:
return HttpResponse(reverse(return_clients))
return render_to_response('items.html', {'items':items, 'client':client, 'item_list':item_list}, context_instance = RequestContext(request))
我以为也许我可以粘贴项目的定义,只是调用该item_list但是不起作用。任何想法
I thought maybe I can just paste the definition of items and just call that item_list but that does not work. Any ideas
items.html
items.html
{% for item in item_list %}
{{item.tiptop_id}
{% endfor %}
推荐答案
从您的评论中:
我得到一个白色屏幕,屏幕上打印了URL。 / tiptop / client在这种情况下。
I get a white screen with the url printed on the screen. /tiptop/client in this case.
因为这是你要求的:
except:
return HttpResponse(reverse(return_clients))
意味着如果上面有任何错误或问题,您的视图将只输出一个包含该URL的响应。也许你打算使用 HttpResponseRedirect
,所以浏览器实际上重定向到URL - 但是你仍然不应该使用一个空白的,除了
This means that if there are any bugs or problems in the above, your view will simply output a response containing just that URL. Maybe you meant to use HttpResponseRedirect
, so the browser actually redirects to the URL - but still you should not use a blank except
, as it prevents you from seeing what is actually going wrong.
若要回答主要问题,请考虑您的 edit_order
视图返回:它给你一个完整的HTML响应与渲染的模板。如何在另一个视图中将其用作查询中的元素?您需要在逻辑上考虑这一点。
To answer the main question, think about what your edit_order
view returns: it gives you a complete HTML response with a rendered template. How could you use that as an element in a query in another view? You need to think logically about this.
一个可能的解决方案是定义一个单独的函数,只需返回所需的数据即可简单的查询 - 这两个视图可以称之为它。这是否符合您的要求?
One possible solution would be to define a separate function which just returns the data you want - as a plain queryset - and both views can call it. Does that do what you want?
这篇关于想从另一个视图django打印出一个项目列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!