如何构建一个get_admin_url / get app_label和类名? [英] How to construct a get_admin_url / get app_label and class name?
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问题描述
我有一个模型方法 _get_admin_url
,并想动态构建网址。
I've got a model method _get_admin_url
and want to construct the url dynamically.
class Person(models.Model):
...
def _get_admin_url(self):
"Returns the admin url."
# return '/admin/some_app/person/%d' %self.id
return '/admin/%s/%s/%d/' %(..., ..., d)
admin_url = property(_get_admin_url)
如何获取app_label和类名的值?还是有更好的方法?
How can I get the values for app_label and class name? Or is there a better way?
推荐答案
您可以使用 反转管理URL
功能
You can use the Reversing admin URLs
feature
from django.core import urlresolvers
c = Choice.objects.get(...)
change_url = urlresolvers.reverse('admin:polls_choice_change', args=(c.id,))
如果你想参考change_list页面,你会做
If you wish to refer the change_list page, you would do
urlresolvers.reverse('admin:%s_%s_changelist' % (app_label, model_name))
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