Django表单：在提交db之前要求确认 [英] Django form: ask for confirmation before committing to db

问题描述

更新：该解决方案可以作为单独的答案找到

Update: The solution can be found as a separate answer

我正在制作一个Django表单，以允许用户将tvshow添加到我的数据库。要做到这一点，我有一个 Tvshow 模型，一个 TvshowModelForm ，我使用通用的基于类的视图 CreateTvshowView / UpdateTvshowView 生成表单。

I am making a Django form to allow users to add tvshows to my db. To do this I have a Tvshow model, a TvshowModelForm and I use the generic class-based views CreateTvshowView/UpdateTvshowView to generate the form.

现在来我的问题：让我们说用户想要添加一个节目到数据库，例如权力的游戏。如果此标题的显示已经存在，我想提示用户确认这确实是不同于数据库中的显示，如果没有类似的显示，我想提交到数据库。如何最好地处理这个确认？

Now comes my problem: lets say a user wants to add a show to the db, e.g. Game of Thrones. If a show by this title already exists, I want to prompt the user for confirmation that this is indeed a different show than the one in the db, and if no similar show exists I want to commit it to the db. How do I best handle this confirmation?

我的一些实验显示在下面的代码中，但也许我会以错误的方式进行。我的解决方案的基础是包括一个隐藏的字段 force ，如果用户得到提示，如果他确定他想提交这些数据，应该设置为1，这样我可以读出这个事情是否为1，以决定用户是否点击再次提交，从而告诉我他想要存储它。

Some of my experiments are shown in the code below, but maybe I am going about this the wrong way. The base of my solution is to include a hidden field force, which should be set to 1 if the user gets prompted if he is sure he wants to commit this data, so that I can read out whether this thing is 1 to decide whether the user clicked submit again, thereby telling me that he wants to store it.

我很想听听你的意见家伙想想如何解决这个问题。

I would love to hear what you guy's think on how to solve this.

views.py

class TvshowModelForm(forms.ModelForm):
    force = forms.CharField(required=False, initial=0)
    def __init__(self, *args, **kwargs):
        super(TvshowModelForm, self).__init__(*args, **kwargs)

    class Meta:
        model = Tvshow
        exclude = ('user')

class UpdateTvshowView(UpdateView):
    form_class = TvshowModelForm
    model = Tvshow
    template_name = "tvshow_form.html"

    #Only the user who added it should be allowed to edit
    def form_valid(self, form):
        self.object = form.save(commit=False)
        #Check for duplicates and similar results, raise an error/warning if one is found     
        dup_list = get_object_duplicates(Tvshow, title = self.object.title)
        if dup_list:
            messages.add_message(self.request, messages.WARNING, 
'A tv show with this name already exists. Are you sure this is not the same one? Click submit again once you\'re sure this is new content'
               )
#            Experiment 1, I don't know why this doesn't work
#            form.fields['force'] = forms.CharField(required=False, initial=1)

#            Experiment 2, does not work: cleaned_data is not used to generate the new form
#            if form.is_valid():
#                form.cleaned_data['force'] = 1

#            Experiment 3, does not work: querydict is immutable
#            form.data['force'] = u'1'

        if self.object.user != self.request.user:
            messages.add_message(self.request, messages.ERROR, 'Only the user who added this content is allowed to edit it.')

        if not messages.get_messages(self.request):
            return super(UpdateTvshowView, self).form_valid(form)
        else:
            return super(UpdateTvshowView, self).form_invalid(form)

推荐答案

我将其发布为答案。在您的表单的清洁方法中，您可以按照所需的方式验证用户的数据。它可能是这样的：

I will post it as an answer. In your form's clean method you can validate user's data in the way you want. It might look like that:

def clean(self):
    # check if 'force' checkbox is not set on the form
    if not self.cleaned_data.get('force'):
        dup_list = get_object_duplicates(Tvshow, title = self.object.title)
        if dup_list:
            raise forms.ValidationError("A tv show with this name already exists. "
                                        "Are you sure this is not the same one? "
                                        "Click submit again once you're sure this "
                                        "is new content")

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