使用Django中的信号创建Feed [英] Creting feed using signals in Django
本文介绍了使用Django中的信号创建Feed的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class StreamItem(models。模型):
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField()
pub_date = models.DateTimeField()
content_object = generic.GenericForeignKey ('content_type','object_id')
def get_rendered_html(self):
template_name ='streams / stream_item_%s.html'%(self.content_type.name)
return render_to_string(template_name,{'object':self.content_object})
def create_stream_item(sender,instance,signal,* args,** kwargs):
#检查对象刚刚创建了
如果在kwargs中创建了
如果kwargs ['created']:
create = True
#获取实例的内容类型
ctype = ContentType.objects.get_for_model(实例)
pub _date = instance.pub_date
如果创建:
si = StreamItem.objects.get_or_create(content_type = ctype,object_id = instance.id,pub_date = pub_date)
#在[Fest,College,Event]中为每个这些模型发送一个post_save信号
作为模型名:
my_signal = dispatch.Signal()
my_signal.connect(create_stream_item,sender = modelname )
然后我创建了获取Feed的视图,只要我创建了 StreamItem 对象。但是,信号部分不仅仅是工作。我只是在了解它,所以我不明白我在哪里错了。请帮助。
解决方案
使用 post_save
信号:
from django.db.models.signals import post_save
for [Fest,College,Event]:
post_save.connect(create_stream_item,sender = model)
Here i have defined a model to create a feed instance in 'models.py':
class StreamItem(models.Model):
content_type = models.ForeignKey(ContentType)
object_id = models.PositiveIntegerField()
pub_date = models.DateTimeField()
content_object = generic.GenericForeignKey('content_type', 'object_id')
def get_rendered_html(self):
template_name = 'streams/stream_item_%s.html' % (self.content_type.name)
return render_to_string(template_name, { 'object': self.content_object })
def create_stream_item(sender, instance, signal, *args, **kwargs):
# Check to see if the object was just created for the first time
if 'created' in kwargs:
if kwargs['created']:
create = True
# Get the instance's content type
ctype = ContentType.objects.get_for_model(instance)
pub_date = instance.pub_date
if create:
si = StreamItem.objects.get_or_create(content_type=ctype, object_id=instance.id, pub_date=pub_date)
# Send a signal on post_save for each of these models
for modelname in [Fest, College, Event]:
my_signal = dispatch.Signal()
my_signal.connect(create_stream_item, sender=modelname)
Then i have created views for getting the feed which are working just fine if I create the StreamItem object from the admin site. But, the signals part isn't just working. I am just learning about it, so, I don't understand where I am wrong. Please help.
解决方案
Use post_save
signal:
from django.db.models.signals import post_save
for model in [Fest, College, Event]:
post_save.connect(create_stream_item, sender=model)
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