Django settings.py变量在模板中 [英] Django settings.py variables in templates

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本文介绍了Django settings.py变量在模板中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我遇到了一个非常奇怪的错误。我的 settings.py 文件中定义了一个应用程序ID:

  CARDSPRING_APP_ID ='################'

这个工作几乎在我网站上的每个页面,除了一个。奇怪的是,其他变量可以工作。在页面的脚本部分,我有以下内容:

  alert(cs appid =+ {{CARDSPRING_APP_ID}} + 
sectoken =+ {{securityToken}} +
timestamp =+ {{timestamp}} +
哈希=+ {{digestedHash}} +
ccnum+ $('。card-number')。val()+
exp+ $(',expiration-month')。val()+ $(',expiration-year')。 val()+
user =+ {{csid}});

当页面呈现时,它评估为

  alert(cs appid =+ + 
sectoken =+ DDFJRMZXD12WVWHFFC ###### +
timestamp =+1346183125 +
hash =+ a929b3aec9179c700c09d ###### +
ccnum+ $('。card-number')。val()+
exp+ $ 。val()+ $('。expiration-year')。val()+
user =+ SG1 ###)

重要的是, {{CARDSPRING_APP_ID}} 被评估为无。有人知道为什么会这样吗?谢谢!



更新



我尝试创建一个 context_processors.py 文件,并确保将其添加到 settings.py 中的相应位置。我仍然没有任何运气 - 它评估在一个页面,但不是在另一个



更新2



使用此命令调用模板:

 返回render_to_response('howto'+ str (number)+'。html',locals(),context_instance = RequestContext(request))

strong>更新3
将其工作 - 需要将其添加到我的settings.py

  TEMPLATE_CONTEXT_PROCESSORS = global_settings.TEMPLATE_CONTEXT_PROCESSORS +(
myapp.context_processors.cardspring,


解决方案

创建一个名为 context_processors.py 的文件,并编写以下上下文处理器:

 从django.conf导入设置

def cardspring(request):
return {'CARDSPRING_APP_ID':settings.CARDSPRING_APP_ID}

然后添加 your.locati您的Django设置文件中的on.context_processors.cardspring TEMPLATE_CONTEXT_PROCESSORS ,其中 your.location 是您的 context_processors.py 文件的位置。


I'm encountering a very strange error. I have an app ID defined in my settings.py file like so:

CARDSPRING_APP_ID = '################'

This works on nearly every page in my site, except for one. Strangely enough, other variables work. In a script section on the page, I have the following:

alert("cs appid=" + {{ CARDSPRING_APP_ID }} + 
" sectoken=" + {{ securityToken }} + 
" timestamp= " +{{ timestamp }} + 
" hash = " + {{ digestedHash }} + 
" ccnum " + $('.card-number').val() + 
" exp" + $('.expiration-month').val() + $('.expiration-year').val() + 
" user = " + {{ csid }});

When the page is rendered, it evaluates to this

alert("cs appid=" +  + 
" sectoken=" + DDFJRMZXD12WVWHFFC###### + 
" timestamp= " +1346183125 + 
" hash = " + a929b3aec9179c700c09d###### + 
" ccnum " + $('.card-number').val() + 
" exp" + $('.expiration-month').val() + $('.expiration-year').val() + 
" user = " + SG1###);

Importantly, {{ CARDSPRING_APP_ID }} has evaluated to nothing. Does anyone know why this might be the case? Thank you!

UPDATE

I tried creating a context_processors.py file as described in the answer below, and made sure to add it to the appropriate spot in settings.py . I still don't have any luck -- it evaluates on one page, but not on the other

UPDATE 2

The template is called with this command:

return render_to_response('howto'+str(number)+'.html',locals(),context_instance= RequestContext(request))

UPDATE 3 Got it to work -- needed to add this to my settings.py

TEMPLATE_CONTEXT_PROCESSORS = global_settings.TEMPLATE_CONTEXT_PROCESSORS + (
    "myapp.context_processors.cardspring",
)

解决方案

Create a file called context_processors.py and write the following context processor:

from django.conf import settings

def cardspring(request):
    return { 'CARDSPRING_APP_ID': settings.CARDSPRING_APP_ID }

Then add your.location.context_processors.cardspring to TEMPLATE_CONTEXT_PROCESSORS in your Django settings file, where your.location is the location of your context_processors.py file.

这篇关于Django settings.py变量在模板中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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