如何在Django中获取完整的URL的服务器名称? [英] How do I get the server name in Django for a complete url?
问题描述
我使用django模板来创建一个电子邮件。我做了这样的事情:
msg_html = render_to_string('email /%s.html'%template_name,context)
msg = EmailMultiAlternatives(subject,msg_text,from_email,to_list)
msg.attach_alternative(msg_html,text / html)
msg.content_subtype =html
msg.send()
我的模板使用如下命名的url模式:
{%url url_name参数%}
哪些工作正常,除了它会呈现相对的URL,如:
/ app_name / url_node / parameter
通常这是足够的,但是由于这是一个电子邮件,我真的需要它是一个完整的URL - 服务器名称前面,如:
http:// localhost:8000 / app_name / url_node / parameter 。
我该怎么做?如何动态获取服务器名称? (我不想硬编码,肯定)。
另一种问题的方法:我如何获取HttpServletRequest.getContextPath()ala Java,而是在Django / Python?
谢谢
使用网站应用程序:
Site.objects.get_current()。domain
直接从文档中获取的示例:
from django.contrib.sites.models import Site
from django.core.mail import send_mail
def register_for_newsletter(request):
#检查表单值等,并订阅用户。
#...
current_site = Site.objects.get_current()
send_mail('感谢订阅%s快讯'%current_site.name,
'感谢您的订阅,我们非常感谢。\\\
\\\
-%s团队'%current_site.name,
'editor @%s'%current_site.domain,
[user.email ])
#...
I'm using django templates to create an e-mail. I do something like this:
msg_html = render_to_string('email/%s.html' % template_name, context)
msg = EmailMultiAlternatives(subject, msg_text, from_email, to_list)
msg.attach_alternative(msg_html, "text/html")
msg.content_subtype = "html"
msg.send()
My template uses named url patterns like so: {% url url_name parameter %}
Which works fine, except it will render a relative url, like: /app_name/url_node/parameter
Usually that is enough, but since this is an e-mail I really need it to be a full url - with the server name prepended, like: http://localhost:8000/app_name/url_node/parameter.
How can I do this? How do I dynamically get the server name? (I don't want to hardcode it for sure).
Another way of asking: how do I get HttpServletRequest.getContextPath() ala Java, but instead in Django/Python?
thanks
Use sites application:
Site.objects.get_current().domain
Example direct from documentation:
from django.contrib.sites.models import Site
from django.core.mail import send_mail
def register_for_newsletter(request):
# Check form values, etc., and subscribe the user.
# ...
current_site = Site.objects.get_current()
send_mail('Thanks for subscribing to %s alerts' % current_site.name,
'Thanks for your subscription. We appreciate it.\n\n-The %s team.' % current_site.name,
'editor@%s' % current_site.domain,
[user.email])
# ...
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