如何比较列表并获得总匹配项数量 [英] How to compare lists and get total matching items count

问题描述

Garage.cars：对象车库具有 FK 的汽车

Person.carwishlst： 对象Person拥有他们想要的汽车的 FK 。

Person.carwishlst: object Person has FK of cars they would like.

在Django中如何实现以下循环？

In Django how to I achieve the following, loop?...

获取车辆总数 x ，该车辆与Garage有所匹配。

Get the total number of cars x the Person has which match the ones the Garage has.

结果：
ie Grange有4辆你想要的车

Outcome: i.e. Grange has 4 cars you want

假设，但让我们说Grange车型有一辆FK cars = models.ManyToManyField（Cars）

Hypothetical, but lets say Grange model has an FK cars = models.ManyToManyField(Cars)

人也有一个FK cars_wishlist = models.ManyToManyField（Cars）

Person also has a FK cars_wishlist = models.ManyToManyField(Cars)

推荐答案

假设 car 和 carwishlst 是列表：

您将执行以下操作

def cars_you_want(cars, carwishlst):
    car_set = [val for val in cars if val in carwishlst]
    return len(car_set)

应该这样做。

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