Symfony如何返回所有登录的活动用户 [英] Symfony how to return all logged in Active Users
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问题描述
我想返回我应用程序的所有登录用户，并将其呈现在我的信息中心中。应从会话检索 user_id 和 user_name （我正在使用外部LDAP库进行身份验证）
I want to return all Logged in users of my application and render it in my Dashboard. The user_id and user_name should be retrieved from the session (I am using an external LDAP Library for authentication)
我在数据库中创建了一个名为 lastActivity 的字段，其中包含最后一次登录时间，然后我可以查询数据库 lastActivity 显示最近2分钟内登录的用户。
I have created a field in the database called lastActivity which will contain the last login time and then I can query the database for lastActivity display users logged in in the last 2 minutes.
ActivityListener.php
<?php
namespace Bnpp\SecurityBundle\EventListener;
use Doctrine\ORM\EntityManager;
//use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use Acme\SecurityBundle\Entity\User;
use Doctrine\Bundle\DoctrineBundle\Registry;
/**
* Listener that updates the last activity of the authenticated user
*/
class ActivityListener
{
protected $securityContext;
protected $entityManager;
public function __construct(SecurityContext $securityContext, EntityManager $entityManager)
{
$this->securityContext = $securityContext;
$this->entityManager = $entityManager;
}
/**
* Update the user "lastActivity" on each request
* @param FilterControllerEvent $event
*/
public function onCoreController(FilterControllerEvent $event)
{
// Check that the current request is a "MASTER_REQUEST"
// Ignore any sub-request
if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
return;
}
// Check token authentication availability
if ($this->securityContext->getToken()) {
$user = $this->securityContext->getToken()->getUser();
if ( ($user instanceof User) && !($user->isActiveNow()) ) {
$user->setLastActivity(new \DateTime('now'));
$this->entityManager->flush($user);
}
}
}
}
Services.yml
Services.yml
services:
activity_listener:
class: Bnpp\SecurityBundle\EventListener\ActivityListener
arguments: [@security.context, @doctrine.orm.entity_manager]
tags:
- { name: kernel.event_listener, event: kernel.controller, method: onCoreController }
用户实体
<?php
namespace Acme\SecurityBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
/**
* User
*
* @ORM\Table(name="users")
* @ORM\Entity(repositoryClass="Acme\SecurityBundle\Entity\UserRepository")
*/
class User implements UserInterface
{
/**
* @var \DateTime
* @ORM\Column(name="LASTACTIVITY", type="datetime")
*/
private $lastActivity;
/**
* @return bool whether the user is active or not
*/
public function isActiveNow()
{
$delay = new\DateTime('2 minutes ago');
return($this->getlastActivity()>$delay);
}
/**
* Set lastActivity
*
* @param\Datetime $lastActivity
* @return User
*/
public function setlastActivity($lastActivity)
{
$this->lastActivity = $lastActivity;
return $this;
}
/**
* Get lastActivity
*
* @return \DateTime
*/
public function getlastActivity()
{
return $this->lastActivity;
}
}
推荐答案
这里有一个很棒的帖子：列出在线用户。
There is a great post here: List online users.
您可以创建一个侦听器，监听 kernel.controller 事件，并在每次用户活动时更新用户字段lastActivity。您可以查看 lastActivity< now（） - 2分钟并更新lastActivity时间戳。
You can create a Listener that listens on the kernel.controller event and updates a user field lastActivity every time a user is active. You can check lastActivity < now()- 2 minutes and update lastActivity timestamp.
注意：如果您不使用FOSUserBundle，请参阅下面的编辑。
1 将此添加到您的用户实体
/**
* Date/Time of the last activity
*
* @var \Datetime
* @ORM\Column(name="last_activity_at", type="datetime")
*/
protected $lastActivityAt;
/**
* @param \Datetime $lastActivityAt
*/
public function setLastActivityAt($lastActivityAt)
{
$this->lastActivityAt = $lastActivityAt;
}
/**
* @return \Datetime
*/
public function getLastActivityAt()
{
return $this->lastActivityAt;
}
/**
* @return Bool Whether the user is active or not
*/
public function isActiveNow()
{
// Delay during wich the user will be considered as still active
$delay = new \DateTime('2 minutes ago');
return ( $this->getLastActivityAt() > $delay );
}
2 创建事件监听器
2 Create Event Listener
<?php
namespace Acme\UserBundle\EventListener;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use FOS\UserBundle\Model\UserManagerInterface;
use FOS\UserBundle\Model\UserInterface;
/**
* Listener that updates the last activity of the authenticated user
*/
class ActivityListener
{
protected $securityContext;
protected $userManager;
public function __construct(SecurityContext $securityContext, UserManagerInterface $userManager)
{
$this->securityContext = $securityContext;
$this->userManager = $userManager;
}
/**
* Update the user "lastActivity" on each request
* @param FilterControllerEvent $event
*/
public function onCoreController(FilterControllerEvent $event)
{
// Check that the current request is a "MASTER_REQUEST"
// Ignore any sub-request
if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
return;
}
// Check token authentication availability
if ($this->securityContext->getToken()) {
$user = $this->securityContext->getToken()->getUser();
if ( ($user instanceof UserInterface) && !($user->isActiveNow()) ) {
$user->setLastActivityAt(new \DateTime());
$this->userManager->updateUser($user);
}
}
}
}
kbd> 3 声明事件侦听器作为服务
parameters:
acme_user.activity_listener.class: Acme\UserBundle\EventListener\ActivityListener
services:
acme_user.activity_listener:
class: %acme_user.activity_listener.class%
arguments: [@security.context, @fos_user.user_manager]
tags:
- { name: kernel.event_listener, event: kernel.controller, method: onCoreController }
你很好去！
1 将此添加到您的用户实体
Same as Step 1 Above
2 创建事件侦听器
<?php
namespace Acme\UserBundle\EventListener;
use Symfony\Component\Security\Core\SecurityContext;
use Symfony\Component\HttpKernel\Event\FilterControllerEvent;
use Symfony\Component\HttpKernel\HttpKernel;
use Doctrine\ORM\EntityManager;
use Acme\UserBundle\Entity\User;
/**
* Listener that updates the last activity of the authenticated user
*/
class ActivityListener
{
protected $securityContext;
protected $entityManager;
public function __construct(SecurityContext $securityContext, EntityManager $entityManager)
{
$this->securityContext = $securityContext;
$this->entityManager = $entityManager;
}
/**
* Update the user "lastActivity" on each request
* @param FilterControllerEvent $event
*/
public function onCoreController(FilterControllerEvent $event)
{
// Check that the current request is a "MASTER_REQUEST"
// Ignore any sub-request
if ($event->getRequestType() !== HttpKernel::MASTER_REQUEST) {
return;
}
// Check token authentication availability
if ($this->securityContext->getToken()) {
$user = $this->securityContext->getToken()->getUser();
if ( ($user instanceof User) && !($user->isActiveNow()) ) {
$user->setLastActivityAt(new \DateTime());
$this->entityManager->flush($user);
}
}
}
}
kbd> 3 声明事件侦听器作为服务
parameters:
acme_user.activity_listener.class: Acme\UserBundle\EventListener\ActivityListener
services:
acme_user.activity_listener:
class: %acme_user.activity_listener.class%
arguments: [@security.context, @doctrine.orm.entity_manager]
tags:
- { name: kernel.event_listener, event: kernel.controller, method: onCoreController }
你很好去！
这篇关于Symfony如何返回所有登录的活动用户的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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