主义2 - ManyToMany + IN子句 [英] Doctrine 2 - ManyToMany + IN clause

问题描述

我有这个模型：

/** @Entity @Table(name="articles") */
class Article {
    /** @Id @GeneratedValue @Column(type="integer") */
    protected $id;

    /** @Column(type="string", length=100, nullable=true) */
    protected $title;

    /** @ManyToOne(targetEntity="User", inversedBy="articles") */   
    protected $author;

    /** @Column(type="datetime") */
    protected $datetime;

    /**
     * @ManyToMany(targetEntity="Game", inversedBy="articles")
     * @JoinTable(name="articles_games",
     *      joinColumns={@JoinColumn(name="article_id", referencedColumnName="id")},
     *      inverseJoinColumns={@JoinColumn(name="game_id", referencedColumnName="id")}
     *      )
     */
    protected $games;

    # Constructor
    public function __construct() {
        $this->datetime = new DateTime();
        $this->games = new \Doctrine\Common\Collections\ArrayCollection();
    }

    # ID
    public function getId() { return $this->id; }

    # TITLE
    public function setTitle($v) { $this->title = $v; }
    public function getTitle() {
        if(empty($this->title)) {
            $game = $this->getFirstGame();
            return ($game instanceof Game) ? $game->getTitle() : NULL;
        } else 
            return $this->title;
    }

    # AUTHOR
    public function setAuthor($v) { $this->author = $v; }
    public function getAuthor() { return $this->author; }

    # DATE & TIME
    public function getDateTime() { return $this->datetime; }
    public function setDateTime($v) { $this->datetime = $v; }

    # GAMES
    public function setGames($value) {
        $except_txt = 'Jedna z przesłanych wartości nie jest instancją klasy Game!';

        if(is_array($value)) {
            foreach($value as $v) {
                if($v instanceof Game) $this->games->add($v);
                else throw new Exception($except_txt);
            }
        } else {
            if($value instanceof Game) $this->games->add($value);
            else throw new Exception($except_txt);
        }
    }
    public function getGames() { return $this->games; }
}

如何使查询看起来像这样

How to make query looking like this

SELECT a FROM Article a WHERE :game_id IN a.games

我有这个（ $ game-> getId（）是一个整数）

I have this (the $game->getId() is an integer)

$articles = $db->createQuery("SELECT a.type FROM Article a WHERE :game_id IN a.games GROUP BY a.type")->setParameter('game_id', $game->getId())->getResult();

但是它给我一个语法错误

But it's returning me an syntax error

[Syntax Error] line 0, col 47: Error: Expected Doctrine\ORM\Query\Lexer::T_OPEN_PARENTHESIS, got 'a'

推荐答案

如果您正在寻找与一个游戏相关的文章：

If you are looking for articles related to one game:

$articles = $db->createQuery("SELECT a FROM Article a JOIN a.games game WHERE game.id = :game_id")
    ->setParameter('game_id', $game->getId())
    ->getResult();

或多个：

$articles = $db->createQuery("SELECT a FROM Article a JOIN a.games game WHERE game.id IN (?,?, ... ?)")
    ->setParameters(array($game1->getId(), $game2->getId() ... $gameN->getId()))
    ->getResult();

这篇关于主义2 - ManyToMany + IN子句的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！