Google Rich Snippet测试工具验证面包屑，但真正的谷歌结果不显示 [英] Google Rich Snippet Test Tool validate breadcrumb but real google result dont show it

问题描述

根据 https://support.google.com/webmasters/ answer / 185417？hl = zh-CN 我使用的是：

 < title> mybiz | prd01 partnumber< / title> 
<！ - 这里有很多标记 - > 
< div itemscope =itemscopeitemtype =http://schema.org/breadcrumb/collection> 
< div itemscope =itemscopeitemtype =http://data-vocabulary.org/Breadcrumb> 
< a href =http：//www.mybiz.com.jr/cat-prod01/itemprop =url> 
< span itemprop =title> cat-prod01< / span> 
< / a> 
< / div> 
< div itemscope =itemscopeitemtype =http://data-vocabulary.org/Breadcrumb> 
< span>>< / span> 
< a href =http：//www.mybiz.com.jr/prod01/itemprop =url> 
< span itemprop =title> prod01< / span> 
< / a> 
< / div> 
< / div> Google Rich Snippet测试工具上的
  

它可以正常工作，片段和孔页面上的< br>
结果在这里 http://www.google .com / webmasters / tools / richsnippets？q =上传：8004ead5f1f7ed7df2ea229e48ac0492

但真正的Google结果不会显示丰富的代码段，有人抱怨
这里的问题使用Schema.org的面包屑没有显示在Google Rich Snippets测试工具和此处 schema.org面包屑导航不工作

有人告诉它还没有准备好，但schema.org不要警告。

我搜索到的网页上的其他页面得到它工作我会改变成类似的东西：

 < title> mybiz | prd01 partnumber< / title> 
<！ - 这里有很多标记 - > 
< div xmlns：v =http://rdf.data-vocabulary.org/#id =BreadCrumbs> 
< span typeof =v：Breadcrumb>& nbsp; 
< a href =http：//www.c.jr/mybiz =v：urlproperty =v：title> mybiz< / a> 
< / span> 
& nbsp;>& nbsp; 
< span typeof =v：Breadcrumb> 
< a href =http：//www.c.jr/catprd01 =v：urlproperty =v：title> cat-prod01< / a> 
< / span> 
& nbsp;>& nbsp; 
< span typeof =v：Breadcrumb> 
< a href =http：//www.c.jr/catprd01/prd01 =v：urlproperty =v：title> prod01< / a> 
< / span> 
< / div> 
  

可以看到它的工作 TOO 这里 http://www.google.com/webmasters/tools/richsnippets?q=uploaded:8004ead6128f340ee942649a82819d22

，但是害怕它不工作 TOO 。有人可以帮助我，当我按照文档和测试工具告诉它可以，但真正的一个不能做什么我可以做什么？

现在，当更改完成时，它不再工作，而在孔页面上，但片段可以工作，等待对真正的Google的影响。

解决方案

你永远不会告诉Google如何行事，你只能要求。有了这个，我的意思是说，您无法确定Google是否会为丰富网页摘要显示您的标记。如果它有效，那么这是正确的。

一个建议是，正如这里的评论所述：https://stackoverflow.com/a/10373534/570796 ，要使用Google的数据词汇表： https://support.google.com/webmasters/answer/185417?hl=zh-CN&topic=1088474&ctx=topic < br>
由于某种原因，这被称为更被接受。但是，再次，您只能标记并请求显示。

As defined by https://support.google.com/webmasters/answer/185417?hl=en I was using the following:

<title>mybiz | prd01 partnumber</title>
<!-- a lot of markup here -->
<div itemscope="itemscope" itemtype="http://schema.org/breadcrumb/collection">
    <div itemscope="itemscope" itemtype="http://data-vocabulary.org/Breadcrumb">
        <a href="http://www.mybiz.com.jr/cat-prod01/" itemprop="url">
            <span itemprop="title">cat-prod01</span>
        </a> 
    </div>
    <div itemscope="itemscope" itemtype="http://data-vocabulary.org/Breadcrumb">
        <span>›</span>
        <a href="http://www.mybiz.com.jr/prod01/" itemprop="url">
            <span itemprop="title">prod01</span>
        </a> 
    </div>
</div> 

on the Google Rich Snippet Test Tool it works ok, the fragment and on the hole page, the
result is here http://www.google.com/webmasters/tools/richsnippets?q=uploaded:8004ead5f1f7ed7df2ea229e48ac0492

but the real Google result dont show the rich snippet, there is someone complaining about problems here Breadcrumb with Schema.org not showing in Google Rich Snippets testing tool and here schema.org Breadcrumb Navigation is not working

There is people telling its not ready but schema.org dont warn about it.

others pages on the web that i searched get it working and i will change to something like it :

<title>mybiz | prd01 partnumber</title>
<!-- a lot of markup here -->
<div xmlns:v="http://rdf.data-vocabulary.org/#" id="BreadCrumbs">
    <span typeof="v:Breadcrumb">&nbsp;
        <a href="http://www.c.jr/mybiz" rel="v:url" property="v:title">mybiz</a>
    </span>
    &nbsp;›&nbsp;          
    <span typeof="v:Breadcrumb">
        <a href="http://www.c.jr/catprd01" rel="v:url" property="v:title">cat-prod01</a>
    </span>
    &nbsp;›&nbsp;
    <span typeof="v:Breadcrumb">
        <a href="http://www.c.jr/catprd01/prd01" rel="v:url" property="v:title">prod01</a>
    </span>
</div>

is possible see its working TOO here http://www.google.com/webmasters/tools/richsnippets?q=uploaded:8004ead6128f340ee942649a82819d22

but im afraid that it dont work TOO.

someone can help me, what can i do when i follow the docs and the test tool tell its ok but the real one not ?

Now when the change is done its dont work anymore when on the hole page but fragment works, waiting for the effect on the real Google.

解决方案

You can never tell Google how to act, you can only request. With this I mean that you can never be sure if Google will show your markup for rich snippets. If it validates, then it's correct.

A suggestion is, as mentioned in the comments here: https://stackoverflow.com/a/10373534/570796, to use Googles data vocabulary: https://support.google.com/webmasters/answer/185417?hl=en&topic=1088474&ctx=topic
This has been known to be more accepted for some reason. But again, you can only mark it up and request for it to be shown..

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