Dojo和取消注册小部件 [英] Dojo and unregistering widgets

问题描述

我很熟悉Dojo Toolkit。我收到错误

 尝试使用id = myButton注册窗口小部件，但该ID已经注册
  

每当我尝试加载dojo内容两次（意味着我通过jQuery.Load加载HTML内容到容器div）。有没有办法在dojo中注销已注册的小部件？我看过一些例子，但是我并没有真正让他们工作。

我的按钮：

 < button dojoType =dijit.form.Buttonid =myButton>按钮< / button> 
  

解决方案

如果您要注销特定的小部件，可以使用他们的 destroy（）或 destroyRecursive（）方法。第二个破坏你正在摧毁的任何小部件（即在表单窗口小部件上调用destroyRecursive也会破坏所有的窗体组件）。

在你的情况下，这听起来好像是在 jQuery.load -

  var widgets = dijit.findWidgets（< containerDiv>）; 
 dojo.forEach（widgets，function（w）{
 w.destroyRecursive（true）; 
}）; 
  

上述代码将注销< containerDiv> ，和保留其关联的DOM节点。要破坏DOM节点，请将 false 传递给 destroyRecursive 。

参考：

http ：//dojotoolkit.org/api/1.3/dijit/_Widget/destroyRecursive

I am new to the Dojo Toolkit. I'm getting the error

Tried to register widget with id=myButton but that id is already registered

whenever I try to load dojo content twice (meaning I load HTML content through jQuery.Load into a container div). Is there a way of unregistering already registered widgets in dojo? I've seen some examples, but I don't really get them working.

My button:

<button dojoType="dijit.form.Button" id="myButton">button</button>

解决方案

If you're looking to unregister specific widgets, you can use their destroy() or destroyRecursive() methods. The second one destroys any widgets inside the one you are destroying (i.e. calling destroyRecursive on a form widget will also destroy all the form components).

In your case, it sounds like your best bet would be to do this before jQuery.load -

var widgets = dijit.findWidgets(<containerDiv>);
dojo.forEach(widgets, function(w) {
    w.destroyRecursive(true);
});

The above code will unregister all widgets in <containerDiv>, and preserve their associated DOM Nodes. To destroy the DOM nodes, pass false to destroyRecursive instead.

Reference:

http://dojotoolkit.org/api/1.3/dijit/_Widget/destroyRecursive

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