dojo dojo.data.ItemFileWriteStore slow ....？ [英] dojo dojo.data.ItemFileWriteStore slow....?

问题描述

我有一些代码可以从一个servlet请求一些数据，并将其呈现在一个dojox.grid.DataGrid中。这似乎相当缓慢！我坚持如何使它更快。任何人都可以帮忙吗？

我正在测试

Dojo 1.34
FF& Chrome。

我的代码删除了dojo.data.ItemFileWriteStore中的所有项目，然后添加了从JSON请求返回的新项目。

  //为WriteStore定义globla var ... 
 var deltaInfo; 
 var rawdataDeltaInfo =< s：property value ='％{deltaTableData}'/> ;; 
 deltaInfo = new dojo.data.ItemFileWriteStore（{
 data：{
 items：rawdataDeltaInfo 
} 
}）; 
  

这部分代码删除所有的存在数据需要2秒，即使它只有30行。任何想法如何使这个更快？

  function requestJSONFeed（）{
 //删除所有现有数据... 
 var allData = deltaInfo._arrayOfAllItems; （i = 0; i< allData.length; i ++）{
 if（allData [i]！= null）{
 deltaInfo.deleteItem（allData [i]）; 
 
} 
} 
 deltaInfo.save（）; 
 
 //使JSON XHR请求... 
 var xhrArgs = {
 url：../secure/jsonServlet，
 handleAs：json 
 preventCache：true，
 load：function（data）{
 //向商店添加新的项目... 
 for（i = 0; i< data.length; i ++）{
 deltaInfo.newItem（data [i]）; 
} 
}，
错误：function（error）{
} 
} 
 
 //调用异步xhrGet 
 var deferred = dojo.xhrGet（xhrArgs）; 
  

}

上面的代码部分添加30个新项目需要4秒。任何关于如何使这个更快的想法？

谢谢！

Jeff Porter

最终代码...

  var xhrArgs = {
 url：.. / secure / jsonServlet，
 handleAs：json，
 preventCache：true，
 load：function（datax）{
 deltaInfo = new dojo.data.ItemFileWriteStore ：{items：datax}}）; 
 var grid = dijit.byId（gridDeltas）; 
 grid.setStore（deltaInfo）; 
}，
错误：功能（错误）{
} 
  

解决方案

尝试跳过穿过现有商店的代码，删除每个项目，然后执行 deltaInfo.save（）。而是根据您的xhr通话建立一个全新的商店，然后使用 dojox.grid.DataGrid.setStore（） 。

I've got some code that requests some data from a servlet, and renders it in a dojox.grid.DataGrid. This seems to be rather slow though! I'm stuck on how to make it faster. Can anyone help out?

I'm testing with

Dojo 1.34 FF & Chrome.

My code remove all items in the dojo.data.ItemFileWriteStore, then adds new ones that come back from a JSON request.

 //Define globla var for the WriteStore...
 var deltaInfo;
 var rawdataDeltaInfo = <s:property value='%{deltaTableData}'/>;
 deltaInfo = new dojo.data.ItemFileWriteStore({
     data: {
         items: rawdataDeltaInfo
     }
 });

This section of code to remove all the existng data take 2seconds, even though it only has 30 rows. Any ideas how to make this quicker?

 function requestJSONFeed(){
     // remove all existing data...
        var allData = deltaInfo._arrayOfAllItems;
     for (i=0;i<allData.length;i++) {
       if (allData[i] != null) {
        deltaInfo.deleteItem(allData[i]);
       }
     }
     deltaInfo.save();

     // make JSON XHR request...
   var xhrArgs = {
  url: "../secure/jsonServlet",
     handleAs: "json",
     preventCache: true,
     load: function(data) {
         // Add new items to the store...
       for (i=0;i<data.length;i++) {
        deltaInfo.newItem(data[i]);
      }
     },
     error: function(error) {
     }
 }

 //Call the asynchronous xhrGet
 var deferred = dojo.xhrGet(xhrArgs);

}

The section of code above to add 30 new items takes 4 seconds. Any ideas on how to make this faster?

Thanks!

Jeff Porter

FINAL CODE...

var xhrArgs = {
url: "../secure/jsonServlet",
 handleAs: "json",
 preventCache: true,
 load: function(datax) {
     deltaInfo = new dojo.data.ItemFileWriteStore({data: {items:datax}});
     var grid = dijit.byId("gridDeltas");
     grid.setStore(deltaInfo);
 },
 error: function(error) {
 }

解决方案

Try skipping the code that walks through the existing store, deletes every item and then does deltaInfo.save(). Instead, create a brand new store based on your xhr call, and then use dojox.grid.DataGrid.setStore().

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