PHP Dom删除元素留下内容 [英] PHP Dom Remove element leave contents

问题描述

我正在尝试根据其ID标签删除某些链接，但留下链接的内容。例如，我想转一下

I am trying to remove certain links depending on their ID tag, but leave the content of the link. For example I want to turn

Some text goes <a href="http://www.domain.tdl/" id="remove">here</a>

至

Some text goes here

我已经尝试使用下面。

$dom = new DOMDocument;
$dom->loadHtml(mb_convert_encoding($html, 'HTML-ENTITIES', "UTF-8"));
$xp = new DOMXPath($dom);

foreach($xp->query('//a[contains(@id="remove")]') as $oldNode) {
$revised = strip_tags($oldNode);
}

$revised = mb_substr($dom->saveXML($xp->query('//body')->item(0)), 6, -7, "UTF-8");
echo $revised;

大致取自这里，但它只是吐出相同的内容 $ html 。

roughly taken from here but it just spits back the same content of $html.

任何想法如何实现这一点？

Any idea's on how I would achieve this?

推荐答案

这是我的功能：

function DOMRemove(DOMNode $from) {
    $sibling = $from->firstChild;
    do {
        $next = $sibling->nextSibling;
        $from->parentNode->insertBefore($sibling, $from);
    } while ($sibling = $next);
    $from->parentNode->removeChild($from);    
}

所以这样：

$dom->loadHTML('Hello <a href="foo"><span>World</span></a>');
$a = $dom->getElementsByTagName('a')->item(0); // get first
DOMRemove($a);

应该给你：

Hello <span>World</span>

要获取具有特定ID的节点，请使用XPath：

To get nodes with a specific ID, use XPath:

$xpath = new DOMXpath($dom);
$node = $xpath->query('//a[@id="something"]')->item(0); // get first
DOMRemove($node);

这篇关于PHP Dom删除元素留下内容的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！