我怎样才能remove从字符串在C＃中引用的字符串？ [英] How can I remove quoted string literals from a string in C#?

问题描述

我有一个字符串：

  

您好援引串和棘手的东西的世界

和想要得到的串减去报件返还。例如，

  

您好，世界

有什么建议？

解决方案

  resultString = Regex.Replace（subjectString，
    @（[']）＃匹配报价，请记住哪一个
    （？：      ＃ 然后...
     （？！\ 1）＃（只要下一个字符是不一样的报价与以前一样）
     。 ＃匹配任何字符
    ）*＃任何次数
    \ 1＃，直到相应的收盘报价
    \ S *＃加上可选空白
    ，
    ，RegexOptions.IgnorePatternWhitespace）;
 

将工作在你的榜样。

  resultString = Regex.Replace（subjectString，
    @（[']）＃匹配报价，请记住哪一个
    （？：      ＃ 然后...
     （？！\ 1）＃（只要下一个字符是不一样的报价与以前一样）
     \\？ ＃匹配任何转义或转义字符
    ）*＃任何次数
    \ 1＃，直到相应的收盘报价
    \ S *＃加上可选空白
    ，
    ，RegexOptions.IgnorePatternWhitespace）;
 

也将处理转义引号。

，以便正常转换

 你好援引\字符串\\和棘手的东西的世界
 

到

 您好，世界
 

I have a string:

Hello "quoted string" and 'tricky"stuff' world

and want to get the string minus the quoted parts back. E.g.,

Hello and world

Any suggestions?

解决方案

resultString = Regex.Replace(subjectString, 
    @"([""'])# Match a quote, remember which one
    (?:      # Then...
     (?!\1)  # (as long as the next character is not the same quote as before)
     .       # match any character
    )*       # any number of times
    \1       # until the corresponding closing quote
    \s*      # plus optional whitespace
    ", 
    "", RegexOptions.IgnorePatternWhitespace);

will work on your example.

resultString = Regex.Replace(subjectString, 
    @"([""'])# Match a quote, remember which one
    (?:      # Then...
     (?!\1)  # (as long as the next character is not the same quote as before)
     \\?.    # match any escaped or unescaped character
    )*       # any number of times
    \1       # until the corresponding closing quote
    \s*      # plus optional whitespace
    ", 
    "", RegexOptions.IgnorePatternWhitespace);

will also handle escaped quotes.

So it will correctly transform

Hello "quoted \"string\\" and 'tricky"stuff' world

into

Hello and world

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