XML解析与Child不值解析 [英] XML parsing with Child not value parsing

问题描述

XML解析与Child not value parsing

  import java.io.File; 
 import java.io.FileInputStream; 
 
 import javax.xml.xpath.XPath; 
 import javax.xml.xpath.XPathConstants; 
 import javax.xml.xpath.XPathFactory; 
 
 import org.w3c.dom.Node; 
 import org.w3c.dom.NodeList; 
 import org.xml.sax.InputSource; 
 
 import com.sun.org.apache.xml.internal.dtm.ref.DTMNodeList; 
 
 public class XPathEvaluator {
 / * 
 * ServiceGroup serviceGroup = new ServiceGroup（）;列表与LT;服务> 
 * requiredServices = new ArrayList< Service>（）;列表与LT;服务> 
 * recommendationsandedServices = new ArrayList< Service>（）; Service service = new 
 * Service（）; 
 * / 
 
 public void evaluateDocument（File xmlDocument）{
 
 try {
 XPathFactory factory = XPathFactory.newInstance（）; 
 XPath xPath = factory.newXPath（）; 
 String requiredServicesExpression =/ Envelope / Header; 
 InputSource requiredServicesInputSource = new InputSource（
 new FileInputStream（xmlDocument））; 
 DTMNodeList requiredServicesNodes =（DTMNodeList）xPath.evaluate（
 requiredServicesExpression，requiredServicesInputSource，
 XPathConstants.NODESET）; 
 System.out.println（requiredServicesNodes.getLength（））; 
 NodeList requiredNodeList =（NodeList）requiredServicesNodes; （int i = 0; i< requiredNodeList.getLength（）; i ++）{
 Node node = requiredNodeList.item（i）; 
 
 
 System.out.println（node.getChildNodes（））; 
 
} 
 
} catch（异常e）{
 e.printStackTrace（）; 
} 
} 
 
 public static void main（String [] argv）{
 XPathEvaluator evaluateator = new XPathEvaluator（）; 
文件xmlDocument = new File（d：//eva.xml）; 
 evaluateator.evaluateDocument（xmlDocument）; 
 
} 
 
} 
  

我的xml是以下是我尝试解析标题信息

 <？xml version =1.0encoding =UTF-8 ？> 
< Envelope> 
<标题> 
< User id =MAKRISH/> 
< Request-Id id =1/> 
< Type name =Response/> 
< Application-Source name =vssversion =1.0/> 
< Application-Destination name =test/> 
< Outgo-Timestamp date =2012-08-24time =14:50:00/> 
< DealerCode> 08301< / DealerCode> 
< Market> 00000< / Market> 
< / Header> 
< / Envelope> 
  

我无法获取Header小孩如何获取它在getchildNodes方法中给我null 。

解决方案

这个相关的问题有一个很好的例子，用xpath解析xml。

我已经调试了你的代码，而getChildNodes调用实际上并不返回null，但它有一个令人困惑的 toString（）。 p>

XML parsing with Child not value parsing

   import java.io.File;
   import java.io.FileInputStream;

   import javax.xml.xpath.XPath;
   import javax.xml.xpath.XPathConstants;
   import javax.xml.xpath.XPathFactory;

   import org.w3c.dom.Node;
   import org.w3c.dom.NodeList;
   import org.xml.sax.InputSource;

   import com.sun.org.apache.xml.internal.dtm.ref.DTMNodeList;

    public class XPathEvaluator {
    /*
   * ServiceGroup serviceGroup = new ServiceGroup(); List<Service>
    * requiredServices = new ArrayList<Service>(); List<Service>
  * recommandedServices = new ArrayList<Service>(); Service service = new
  * Service();
  */

public void evaluateDocument(File xmlDocument) {

    try {
        XPathFactory factory = XPathFactory.newInstance();
        XPath xPath = factory.newXPath();
        String requiredServicesExpression = "/Envelope/Header";
        InputSource requiredServicesInputSource = new InputSource(
                new FileInputStream(xmlDocument));
        DTMNodeList requiredServicesNodes = (DTMNodeList) xPath.evaluate(
                requiredServicesExpression, requiredServicesInputSource,
                XPathConstants.NODESET);
        System.out.println(requiredServicesNodes.getLength());
        NodeList requiredNodeList = (NodeList) requiredServicesNodes;

        for (int i = 0; i < requiredNodeList.getLength(); i++) {
            Node node = requiredNodeList.item(i);
            System.out.println(node.getChildNodes());

        }

    } catch (Exception e) {
        e.printStackTrace();
    }
}

public static void main(String[] argv) {
    XPathEvaluator evaluator = new XPathEvaluator();
    File xmlDocument = new File("d://eva.xml");
    evaluator.evaluateDocument(xmlDocument);

 }

}

my xml is following in this i am try to parse header information

   <?xml version="1.0" encoding="UTF-8"?>
   <Envelope>
       <Header>
            <User id="MAKRISH"/>
            <Request-Id id="1"/>
            <Type name="Response"/>
            <Application-Source name="vss" version="1.0"/>
            <Application-Destination name="test" />
            <Outgo-Timestamp date="2012-08-24" time="14:50:00"/>
            <DealerCode>08301</DealerCode>
            <Market>00000</Market>
        </Header>
   </Envelope>

i am not able to get Header child how can i get them it is giving me null on getchildNodes method. i have check for many solution but get any thing.

解决方案

The accepted answer to this related question has a good example of parsing xml using xpath.

I've debugged into your code, and the getChildNodes call is in fact not returning null, but it has got a confusing toString().

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