C ++模板的十进制和任意进制之间的转换 [英] c++ template for conversion between decimal and arbitrary base

问题描述

有一个C ++结构或模板（在任何库），可以让我做的十进制和任何其他基（更象是位集可以做的）之间的转换？

Is there a c++ structure or template (in any library) that allows me to do conversion between decimal and any other base (much like what bitset can do) ?

推荐答案

是的，你可以使用无符号整型：

unsigned int n =   16; // decimal input
unsigned int m = 0xFF; // hexadecimal input

std::cout << std::dec << "Decimal: " << n << ", " << m << std::endl;
std::cout << std::hex << "Hexadecimal: 0x" << n << ", 0x" << m << std::endl;

八也支持，但其它基地你最好写你自己的算法 - 它本质上是一个三班轮在C：

Octal is also supported, though for other bases you had best write your own algorithm - it's essentially a three-liner in C++:

std::string to_base(unsigned int n, unsigned int base)
{
    static const char alphabet[] = "0123456789ABCDEFGHI";
    std::string result;
    while(n) { result += alphabet[n % base]; n /= base; }
    return std::string(result.rbegin(), result.rend());
}

逆无符号整数from_base（标准::字符串，无符号整型基地）的功能是相似的。

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