在java中排序xml元素 [英] sort the xml elements in java

查看:395
本文介绍了在java中排序xml元素的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以我需要用java中的姓氏对xml文件中的数据进行排序,这里是xml文件。

So I need to sort the data from the xml file by last name in java, and here is the xml file

        <employeeList>
        <employee>
            <name>
                <last>Johnson</last>
                <first>Jason</first>
            </name>
        </employee>
        <employee>
            <name>
                <last>McGrady</last>
                <first>Mike</first>
            </name>
        </employee>
        <employee>
            <name>
                <last>Allen</last>
                <first>Chris</first>
            </name>
        </employee>
        <employee>
            <name>
                <last>Zeller</last>
                <first>Tom</first>
            </name>
        </employee>

        <employee>
            <name>
                <last>Camp</last>
                <first>Alex</first>
            </name>
        </employee>

这里是我到目前为止,能够打印代码,但是如何排序他们以姓氏?请帮助

and here is what I have so far, able to print the code out, but how do I sort them by last name? please help

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.w3c.dom.Node;
import org.w3c.dom.Element;
import java.io.File;
public class SortLastName {
   public static void main(String[] args)
 {    
  try{ 
     File employeesList = new File("employees.xml");
     DocumentBuilderFactory employeesFactory = DocumentBuilderFactory.newInstance();
     DocumentBuilder employeesBuilder = employeesFactory.newDocumentBuilder();
    Document employees = employeesBuilder.parse(employeesList);
     employees.getDocumentElement().normalize();
     NodeList nEmployeesList = employees.getElementsByTagName("employee");
     int totalEmployees = nEmployeesList.getLength();

  for (int a = 0; a < totalEmployees; a++)
  {
     Node list = nEmployeesList.item(a);   
     if (list.getNodeType() == Node.ELEMENT_NODE)
     {
        Element information = (Element) list;
        String lastName = information.getElementsByTagName("last").item(0).getTextContent();
        String firstName = information.getElementsByTagName("first").item(0).getTextContent();
        System.out.println("Last name: " + lastName );
        System.out.println("First name: " + firstName);
        System.out.println();
        }
     }
     }
  catch(Exception e)
  {
     e.printStackTrace();
  }

}
}

推荐答案

将每个名称添加到类似于 ArrayList

Add each name to something like an ArrayList

    ArrayList<String> names = new ArrayList<>(25);

    /*...*/

    String lastName = information.getElementsByTagName("last").item(0).getTextContent();
    String firstName = information.getElementsByTagName("first").item(0).getTextContent();
    names.add(lastName + " " + firstName);

    /*.../

    Collections.sort(names);

您可能会发现收藏教程也有兴趣...

You might find the Collections tutorial of some interest as well...

这篇关于在java中排序xml元素的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆