比较Java中的双打给出了奇怪的结果 [英] Comparing doubles in Java gives odd results

问题描述

我真的不明白为什么会发生以下情况：

I really can'get my head around why the following happens:

Double d = 0.0;
System.out.println(d == 0); // is true
System.out.println(d.equals(0)); // is false ?!

然而，这样可以预期：

Double d = 0.0;
System.out.println(d == 0.0); // true
System.out.println(d.equals(0.0)); // true

我很乐意这与autoboxing有关，但我真的很不知道为什么 0 会在使用 == 运算符时使用不同的方式，而 .equals 被称为。

I'm positive that this is related to autoboxing in some way, but I really don't know why 0 would be boxed differently when the == operator is used and when .equals is called.

这不是隐含地违反了 code>合同？

Doesn't this implicitly violate the equals contract ?

  *  It is reflexive: for any non-null reference value
  *     x, x.equals(x) should return
  *     true.

编辑：

感谢您的快速答案。我认为它是不同的盒子，真正的问题是：为什么是不同的盒子？我的意思是，如果 d == 0d 比 d.equals（0d）更直观， ，但是如果 d == 0 看起来像一个整数是 true than'intuitive' d.equals（0）也应该是真的。

Thanks for the fast answers. I figured that it is boxed differently, the real question is: why is it boxed differently ? I mean that this would be more intuitive if d == 0d than d.equals(0d) is intuitive and expected, however if d == 0 which looks like an Integer is true than 'intuitively' d.equals(0) should also be true.

推荐答案

只需将其更改为

System.out.println(d.equals(0d)); // is false ?! now true

您正在与 Integer 0

System.out.println(d.equals(0)); // is false ?!

0 将自动装箱至整数，并且Integer的一个实例将被传递给 equals（）方法 Double 类，它将像

0 will be autoboxed to Integer and an instance of Integer will be passed to equals() method of Double class, where it will compare like

@Override
    public boolean equals(Object object) {
        return (object == this)
                || (object instanceof Double)
                && (doubleToLongBits(this.value) == doubleToLongBits(((Double) object).value));
    }

当然会返回 false

当您使用 = = 它比较值，所以不需要autobox，它直接对值进行操作。其中 equals（）接受 Object 所以如果你尝试调用 d1.equals（0） ， 0 不是Object，所以它将执行自动装箱，它将它打包成一个对象的整数。

when you do comparison using == it compares values so there is no need to autobox , it directly operates on value. Where equals() accepts Object so if you try to invoke d1.equals(0) , 0 is not Object so it will perform autoboxing and it will pack it to Integer which is an Object.

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