使用servlet从服务器下载Excel文件 [英] Downloading Excel file from server using servlets
问题描述
提前感谢
要点:只需要获得一个 InputStream
( FileInputStream
是合适的)并写它通过 OutputStream noreferrer> Java IO 的方式。基本上都是这样您只需要注意设置正确的响应标头,以便浏览器了解如何处理。 Content-Type
头将指示webbrowser是什么样的文件,以便浏览器知道要使用哪个应用程序打开它。
这是一个开始示例:
protected void doGet(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException {
String filename = URLDecoder.decode(request.getPathInfo(),UTF-8);
文件文件=新建文件(/ path / to / files,filename);
response.setHeader(Content-Type,getServletContext()。getMimeType(file.getName()));
response.setHeader(Content-Length,file.length());
response.setHeader(Content-Disposition,inline; filename = \+ file.getName()+\);
BufferedInputStream input = null;
BufferedOutputStream output = null;
try {
input = new BufferedInputStream(new FileInputStream(file));
output = new BufferedOutputStream(response.getOutputStream());
byte [] buffer = new byte [8192]; (int length = 0;(length = input.read(buffer))> 0;){
output.write(buffer,0,length);
}
} finally {
if(output!= null)try {output.close(); } catch(IOException ignore){}
if(input!= null)try {input.close(); } catch(IOException ignore){}
}
}
映射这个servlet在 web.xml
中 url-pattern
/ files / *
,以便您可以通过 http://example.com/contextname/files/filename.xls
获取excel文件。
如果它实际上是一个 xlsx
文件,这不是平均servletcontainer默认的( ServletContext#getMimeType()
然后返回 application / octet-stream
而不是所需的 xlsx
内容类型),那么您还需要将以下条目添加到 web.xml
中:
< mime-mapping>
< extension> xlsx< / extension>
< mime-type> application / vnd.openxmlformats-officedocument.spreadsheetml.sheet< / mime-type>
< / mime-mapping>
有关文件servlet的更高级示例,您可能会发现这篇文章也很有用,它也支持每个下载简历。
I have an Excel file on the server side. How I can display it on client side browser using servlets?
Thanks in advance.
To the point: just get an InputStream
of it somehow (FileInputStream
is suitable) and write it to the OutputStream
of the response the usual Java IO way. That's basically all. You'll only need to take care that you set the right response headers, so that the browser understands what to do with it. The Content-Type
header will instruct the webbrowser what kind of file it is so that the browser knows which application to use to open it.
Here's a kickoff example:
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String filename = URLDecoder.decode(request.getPathInfo(), "UTF-8");
File file = new File("/path/to/files", filename);
response.setHeader("Content-Type", getServletContext().getMimeType(file.getName()));
response.setHeader("Content-Length", file.length());
response.setHeader("Content-Disposition", "inline; filename=\"" + file.getName() + "\"");
BufferedInputStream input = null;
BufferedOutputStream output = null;
try {
input = new BufferedInputStream(new FileInputStream(file));
output = new BufferedOutputStream(response.getOutputStream());
byte[] buffer = new byte[8192];
for (int length = 0; (length = input.read(buffer)) > 0;) {
output.write(buffer, 0, length);
}
} finally {
if (output != null) try { output.close(); } catch (IOException ignore) {}
if (input != null) try { input.close(); } catch (IOException ignore) {}
}
}
Map this servlet in web.xml
on an url-pattern
of /files/*
so that you can get the excel file by http://example.com/contextname/files/filename.xls
.
If it's actually an xlsx
file, which isn't by default recognized by the average servletcontainer yet (the ServletContext#getMimeType()
would then return application/octet-stream
instead of the desired xlsx
content type), then you need to add the following entry to the web.xml
as well:
<mime-mapping>
<extension>xlsx</extension>
<mime-type>application/vnd.openxmlformats-officedocument.spreadsheetml.sheet</mime-type>
</mime-mapping>
For a more advanced example of a file servlet you may find this article useful as well, it supports under each download resumes as well.
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