Drupal Session独立脚本的用户标识 [英] Drupal Session User id for independent script
问题描述
对不起,我是新来的drupal。谢谢你的时间。
Drupal的cron.php是使用库的简单php脚本的完美示例在Drupal的/ includes目录。该文件中的关键行是:
include_once'./includes/bootstrap.inc';
drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);
如果您将自己的代码包含在内,您的a.php文件将可以访问所有Drupal的上下文和图书馆。
I am creating a simple script say a.php. I know that drupal 6 creates a session etc. So in my a.php I am trying to print_r($_SESSION); but that doesnt seem to work. What is the best way to get the logged in users userid in my program?
Sorry I am new to drupal. Thank you for your time.
Drupal's cron.php is a perfect example of a "simple" php script that uses the libraries in Drupal's /includes directory. The key lines in that file are:
include_once './includes/bootstrap.inc';
drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);
if you include those in your own code, your a.php file will have access to all of Drupal's context and libraries.
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