CoreData - 重复现有对象 [英] CoreData - Duplicate existing object
问题描述
movement2 = [NSEntityDescription
insertNewObjectForEntityForName:@Movement
inManagedObjectContext: self.managedObjectContext];
movement2.name = movement.name;
movement2.value = movement.value;
movement2.date = movement.date;
...
它的工作原理。但是...
有没有办法将运动的所有值复制到
NSManagedObject与NSObject不同,提供了一个API来迭代超过其属性和关系。或者说,它是实体描述。它不是一个单行的。
movement2 = [NSEntityDescription insertNewObjectForEntityForName:@Movement
inManagedObjectContext :self.managedObjectContext];
NSEntityDescription * entity = [运动实体];
for(NSString * propertyName in [entity propertiesByName]){
[movement2 setValue:[movement valueForKey:propertyName] forKey:propertyName];
}
请参阅文档,了解更多详情。
这将足以克隆大多数对象。如果数据库结构正确,那么以这种方式复制关系,它们的反向关系也将被更新。所以,如果你的运动与运动方向有一个关系,并且运动方向有一个反向的一对多关系 parentMovements
,这个 parentMovements 在调用上述代码之后,code> set将同时具有
运动
和 movement2
。
Hi would like to duplicate an object from my core data db. Right now I'm using
movement2 = [NSEntityDescription
insertNewObjectForEntityForName:@"Movement"
inManagedObjectContext:self.managedObjectContext];
movement2.name = movement.name;
movement2.value = movement.value;
movement2.date = movement.date;
...
and it works. but...
Is there any way to copy all the values of movement
to movement2
, in one line of code?
NSManagedObject, unlike NSObject, provides an API to iterate over its attributes and relationships. Or, rather, it's entity description does. It isn't a one-liner, though.
movement2 = [NSEntityDescription insertNewObjectForEntityForName:@"Movement"
inManagedObjectContext:self.managedObjectContext];
NSEntityDescription *entity = [movement entity];
for (NSString *propertyName in [entity propertiesByName]) {
[movement2 setValue:[movement valueForKey:propertyName] forKey:propertyName];
}
See the documentation for more details.
This will be enough to clone most of the objects. If database structure is correct, then copying relationships this way, their inverse ones will be updated as well. So, if your Movement had a relationship with, say, MovementDirection, and MovementDirection has an inverse 1-to-many relation parentMovements
, this parentMovements
set will have both movement
and movement2
inside after you call the code above.
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