JavaScript获取所有加载的脚本 [英] JavaScript Get all Loaded Scripts

问题描述

我正在尝试创建一个Javascript函数，返回所有加载的javascript文件。例如：

我加载jquery.js，jquery.somescript.js和tinymce.js

我想要一个函数以脚本格式返回所有内容（所以如果我要保存并再次运行返回文本），就像我已经调用上述文件一样工作。另外，如果TinyMCE加载了15个JS的fies，它也应该返回。

我希望这不是太混乱了，但任何帮助将不胜感激！ p>

感谢提前！

解决方案

getElementsByTagName 应该让你开始：

  var scripts = document.getElementsByTagName（'script'）; 
 // TODO：循环并阅读src属性
  

I am trying to create a Javascript function that will return all javascript files loaded. For Example:

I load jquery.js, jquery.somescript.js, and tinymce.js

I want a function to return everything in script format (so if I were to save and run the return text again) it would work just as if I had called the files described above. Also if TinyMCE loads 15 JS fies, it should return as well.

I hope that isn't too confusing to understand, but any help would be greatly appreciated!

Thanks in Advance!

解决方案

getElementsByTagName should get you started:

var scripts = document.getElementsByTagName('script');
// TODO: loop and read the src attribute

这篇关于JavaScript获取所有加载的脚本的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！