Eclipse：在块中找到可以抛出异常的行 [英] Eclipse: find lines in a block that can throw exceptions

问题描述

我正在看代码，看起来像

I'm looking at code that looks like

try {
     // Lots of things here.
     // More than I'd like to individually hover over every time I see this
} 
catch (Exception e) {
     // doesn't matter
}

对于try块中的任何特定方法，我可以找到它抛出的检查异常。有没有办法突出显示可能会引发一些检查异常的所有行？

For any particular method in the try block, I can find what checked exceptions it throws. Is there any way to highlight all lines that could throw some checked exception?

一般来说，我想我可以删除catch块，改变方法签名来抛出异常，在这一点上，我可以看到抛出的方法中的所有行一个例外（Nevermind：see the update）。

In general, I guess I could perhaps remove the catch block, changing the method signature to throw Exception, at which point, I can see all lines in the method that throw an exception (Nevermind: see the update).

在这种情况下，这甚至不会很好地工作，因为代码在JSP中。

In this case, that won't even work nicely, because the code is in a JSP.

注意：如果重要，我使用MyEclipse标准。

Note: if it matters, I'm using MyEclipse standard.

更新：标记出现在，但在这种情况下根本不做任何事情。我问了这个问题，因为我认为关于这个上下文的一些事情使得这个预期的行为，但它看起来像是一个奇怪的边缘案例或错误。

Update: Mark occurrences is on, but simply does nothing in this case. I asked the question because I thought that something about the context made this expected behavior, but it looks like it's a weird edge case or bug.

推荐答案

在eclipse中，如果启用突出显示事件并选择异常，它会突出显示正在被catch块捕获的（已检查）异常的所有行。

In eclipse, if you enable "highlight occurrences" and select Exception, it would highlight all lines that are throwing a (checked) exception that is being caught by the catch block.

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