Checkstyle上的类变量 [英] Checkstyle on class variable

问题描述

  class Test {
 private int x = 1; 
 
 public void set（int x）{
 this.x = x; 
} 
} 
  

在上述情况下，它调用将x声明为final然而，将x声明为final将会在构造函数中初始化错误。什么是catch？

解决方案

你不能更改静态最终字段的值。

如果您真的需要x静态，请将您的方法更改为

  public static void setX（int newX） {
 [...] 
  

请记住，在静态方法this不能使用。

这应该可以解决你的问题。

Check style says that for a private class variable "must be declared final".

class Test {
    private int x=1;

    public void set(int x) {
        this.x = x;
    }
}

In the above case it calls to declare x as final however declaring x as final would give error on initializing it in the constructor. What's the catch?

解决方案

you cannot change the value of a static final field.

if you really need x to be static, change your method to

public static void setX(int newX){
    [...]

keep in mind, that in static methods "this" cannot be used.

this should solve your problem.

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