匿名JavaScript函数究竟是什么f => f做? [英] What exactly does the anonymous JavaScript function f => f do?
问题描述
我正在使用一个具有函数作为参数的函数的第三方库。我正在做一些条件检查来决定是否添加一个特定的函数作为参数,在某些情况下,我不想提供一个函数。在这种情况下提供null会引发错误。
I'm using a third-party library that has a function that takes functions as arguments. I'm doing some conditional checks to decide whether or not to add a particular function as a parameter and in some cases I don't want to provide a function. Providing null in that cases throws an error.
我发现这个代码有效,但我完全不了解发生了什么。
I found this code which works, but I don't fully understand what's happening.
compose(__DEV__ ? devTools() : f => f)
是 f => f
相当于()=> {}
一个空的匿名函数?
Is f => f
equivalent to () => {}
an empty anonymous function?
推荐答案
f => f
类似*到 function(f){return f;
如此接近,但不完全符合您的预期。
So close, but not quite what you expected.
相关。他们在其他情况下非常相关。
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