为什么我不能捕获EJB异常? [英] Why can't I catch EJB exceptions?
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问题描述
@Stateless
public class UserEJB {
@PersistenceContext
实体管理器
public String getUserName(User user){
return user.getName();
}
public用户fetchUserByEmail(String email){
用户user = em.createNamedQuery(User.findByEmail,User.class).setParameter(电子邮件,电子邮件).getSingleResult();
返回用户;
}
public用户fetchUserById(int id){
返回em.createNamedQuery(User.findByUserId,User.class).setParameter(userId,id)。 getSingleResult();
}
public List< User> fetchAllUsers(){
return em.createNamedQuery(User.findAll,User.class).getResultList();
}
}
@Named(value =userController)
@RequestScoped
public class UserController {
private User user = new User();
@EJB
UserEJB userEJB;
@Inject
SecurityController securityController;
public UserController(){
}
public void login(ActionEvent event){
try {
用户userLogin = userEJB.fetchUserByEmail(user.getEmail());
} catch(Exception e){
}
if(userLogin.getPassword()。equals(user.getPassword())){
securityController.setIsLoggedIn(true);
securityController.setIsAdmin(true);
securityController.setUser(user);
}
}
/ **
* @返回用户
* /
public User getUser(){
返回用户;
}
/ **
* @param用户设置
* /
public void setUser(User user){
this.user = user;
}
解决方案
.out.printlns在代码中?一个在异常处理程序中,一个在if语句之前。你得到什么?
看看代码我会说你将能够捕获异常,这应该是一个JPA异常包装在一个EJB中。 p>
I can't seem to catch exceptions such as NoResultException or EJBException in my java ee 6 project. Is there something I am doing wrong? I have caught exceptions outside the EJB container but this is my first time using EJB. Thanks.
@Stateless
public class UserEJB {
@PersistenceContext
EntityManager em;
public String getUserName(User user) {
return user.getName();
}
public User fetchUserByEmail(String email) {
User user = em.createNamedQuery("User.findByEmail", User.class).setParameter("email", email).getSingleResult();
return user;
}
public User fetchUserById(int id) {
return em.createNamedQuery("User.findByUserId", User.class).setParameter("userId", id).getSingleResult();
}
public List<User> fetchAllUsers() {
return em.createNamedQuery("User.findAll", User.class).getResultList();
}
}
@Named(value = "userController")
@RequestScoped
public class UserController {
private User user = new User();
@EJB
UserEJB userEJB;
@Inject
SecurityController securityController;
public UserController() {
}
public void login(ActionEvent event) {
try {
User userLogin = userEJB.fetchUserByEmail(user.getEmail());
} catch (Exception e) {
}
if (userLogin.getPassword().equals(user.getPassword())) {
securityController.setIsLoggedIn(true);
securityController.setIsAdmin(true);
securityController.setUser(user);
}
}
/**
* @return the user
*/
public User getUser() {
return user;
}
/**
* @param user the user to set
*/
public void setUser(User user) {
this.user = user;
}
解决方案
What if you put two System.out.printlns in the code? One in the exception handler and one right before the if statement. What do you get?
Looking at the code I would say you would be able to catch the exception, which should be a JPA exception wrapped in an EJB one.
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