如何使用python smtplib将邮件发送给多个收件人？ [英] How to send email to multiple recipients using python smtplib?

问题描述

经过多次搜索，我找不到如何使用smtplib.sendmail发送给多个收件人。问题是每次发送邮件时，邮件头将显示为包含多个地址，但实际上只有第一个收件人才能收到邮件。

问题似乎这是 email.Message 模块期望与 smtplib.sendmail（） 功能。

简而言之，要发送给多个收件人，您应该设置标题作为一串逗号分隔的电子邮件地址。 sendmail（）参数 to_addrs 但是应该是一个电子邮件地址列表。

  from email.MIMEMultipart import MIMEMultipart 
 from email.MIMEText import MIMEText 
 import smtplib 
 
 msg = MIMEMultipart（） 
 msg [Subject] =示例
 msg [From] =[e-mail]
 msg [To] =[e-mail]， reynolds @ example.com，firefly @ example.com
 msg [Cc] =serenity @ example.com，inara @ example.com
 body = MIMEText（example email body） 
 msg.attach（body）
 smtp = smtplib.SMTP（mailhost.example.com，25）
 smtp.sendmail（msg [From]，msg [To ] .split（，）+ msg [Cc]。split（，），msg.as_string（））
 smtp.quit（）
  / pre> 
 
解决方案
这个真的很好用，我花了很多时间尝试多种变体。 p> 
 
 
  import smtplib 
 from email.mime.text import MIMEText 
 
s = smtplib.SMTP（' smtp.uk.xensource.com'）
 s.set_debuglevel（1）
 msg = MIMEText（body）
 sender ='[e-mail]'
 recipient = ['john.doe @ example.com'，'[e-mail]'] 
 msg ['Subject'] =subject line
 msg ['From'] = sender 
 msg [ 'to'] =，.join（recipient）
 s.sendmail（发件人，收件人，msg.as_string（））
  
 
After much searching I couldn't find out how to use smtplib.sendmail to send to multiple recipients.  The problem was every time the mail would be sent the mail headers would appear to contain multiple addresses, but in fact only the first recipient would receive the email.

The problem seems to be that the email.Message module expects something different than the smtplib.sendmail() function.

In short, to send to multiple recipients you should set the header to be a string of comma delimited email addresses.  The sendmail() parameter to_addrs however should be a list of email addresses.
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
import smtplib

msg = MIMEMultipart()
msg["Subject"] = "Example"
msg["From"] = "[e-mail]"
msg["To"] = "[e-mail],[e-mail],[e-mail]"
msg["Cc"] = "[e-mail],[e-mail]"
body = MIMEText("example email body")
msg.attach(body)
smtp = smtplib.SMTP("mailhost.example.com", 25)
smtp.sendmail(msg["From"], msg["To"].split(",") + msg["Cc"].split(","), msg.as_string())
smtp.quit()

解决方案
This really works, I spent a lot of time trying multiple variants.
import smtplib
from email.mime.text import MIMEText

s = smtplib.SMTP('smtp.uk.xensource.com')
s.set_debuglevel(1)
msg = MIMEText("""body""")
sender = '[e-mail]'
recipients = ['[e-mail]', '[e-mail]']
msg['Subject'] = "subject line"
msg['From'] = sender
msg['To'] = ", ".join(recipients)
s.sendmail(sender, recipients, msg.as_string())


                        
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