访问内存映射I / O [英] Access Memory Mapped I/O
问题描述
给定:
电机1映射到0x60000000
电机2映射到0x50000000
以下是当前32位寄存器的定义
REGISTER NAME | BYTE OFFSET |注意
--------------------------------------------- -------------------------
motor_interrupt 0x00服务中断
motor_status 0x01启用按需访问状态元素
motor_command 0x02启用电机命令
注册名称| NAME | BITS |访问类型| DESC
--------------------------------------------- -------------------------------------
motor_interrupt_register
关闭0当电机转换到关闭位置时,R / W为高电平
OPEN 1当电机转换到OPEN位置时,R / W为高电平
RESERVED 2.31 N / A保留以备将来使用
motor_status
速度0.2 R速度计数/秒
状态3 R电机的当前状态
POSITION 4.13 R电机的当前位置
RESERVED 14.31 n / a保留为未来使用
我发现使用给定的C ++代码很难看到,在这一点上我是知道我需要访问regi ster_name并将其位设置为执行特定任务或读取注册名称以获取状态。
如果在c ++代码中使用它,我想我可以理解它。给定的是一个自动门系统(我没有写出按钮的细节)。我需要访问register_name或c ++中的byte_offset吗?
您的帮助将非常欣赏
C / C ++例如读取中断/状态寄存器:
volatile uint32_t * const motor1 =(uint32_t *)0x60000000; //电机1和2的基址
volatile uint32_t * const motor2 =(uint32_t *)0x50000000;
枚举//从基址寄存器偏移
{
motor_interrupt,// 0x00 - 服务中断
motor_status,// 0x01 - 启用按需访问状态元素
motor_command // 0x02 - 启用电机命令
}
//读状态/中断寄存器
uint32_t current_int_1 = motor1 [motor_interrupt];
uint32_t current_int_2 = motor2 [motor_interrupt];
uint32_t current_status_1 = motor1 [motor_status];
uint32_t current_status_2 = motor2 [motor_status];
类似于将32位值写入命令寄存器:
motor1 [motor_command] = 0x8000 | (0x12 <6)| 0×01;
motor2 [motor_command] = 0x0;
I am very new to embedded system programming, I just need to learn how to manipulate the given via c++ code.
Given:
Motor 1 is mapped to 0x60000000
Motor 2 is mapped to 0x50000000
the following are the definitions of current 32-bit registers
REGISTER NAME | BYTE OFFSET | NOTES
----------------------------------------------------------------------
motor_interrupt 0x00 service interrupts
motor_status 0x01 enable on demand access to status elements
motor_command 0x02 enable command of the motor
REGISTER NAME | NAME | BITS | ACCESS TYPE | DESC
----------------------------------------------------------------------------------
motor_interrupt_register
CLOSED 0 R/W high when motor transitions to CLOSED position
OPEN 1 R/W high when motor transitions to OPEN position
RESERVED 2.31 N/A reserved for future use
motor_status
SPEED 0.2 R speed in counts/seconds
STATE 3 R current state of motor
POSITION 4.13 R current position of the motor
RESERVED 14.31 n/a reserved for future use
I find it hard to see a sample c++ code using the given, At this point what i know is I need to access the register_name and set their bits to perform specific task or read the register name to get the status for example.
I think I can understand it more if it is used in a c++ code. The given is a automatic door system ( i didnt write the button details). Will I need to access the register_name or the byte_offset in c++?
Your help would be very much appreciated
C/C++ example to read interrupt/status registers:
volatile uint32_t * const motor1 = (uint32_t *)0x60000000; // base addresses for motors 1 and 2
volatile uint32_t * const motor2 = (uint32_t *)0x50000000;
enum // register offsets from base address
{
motor_interrupt, // 0x00 - service interrupts
motor_status, // 0x01 - enable on demand access to status elements
motor_command // 0x02 - enable command of the motor
}
// read status/interrupt registers
uint32_t current_int_1 = motor1[motor_interrupt];
uint32_t current_int_2 = motor2[motor_interrupt];
uint32_t current_status_1 = motor1[motor_status];
uint32_t current_status_2 = motor2[motor_status];
Similarly to write 32 bit values to to the command registers:
motor1[motor_command] = 0x8000 | (0x12 << 6) | 0x01;
motor2[motor_command] = 0x0;
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