8位纯文本的DES加密结果为16字节数组 [英] DES encryption of 8 bytes plain text results in 16 bytes array

问题描述

我正在使用这个代码来加密一个8字节的8字节的PlainText，但结果总是一个16字节的数组。

I am using this code to encrypt a 8 bytes PlainText with a 8 bytes Key but the result is always a 16 bytes array.

public static byte[] Encrypt(byte[] PlainText, byte[] key)
{
    MemoryStream ms = new MemoryStream();
    DESCryptoServiceProvider mDES = new DESCryptoServiceProvider();
    mDES.Mode = CipherMode.ECB;
    mDES.Key = key;

    CryptoStream encStream = new CryptoStream(ms, mDES.CreateEncryptor(), CryptoStreamMode.Write);
    BinaryWriter bw = new BinaryWriter(encStream);

    bw.Write(PlainText);
    bw.Close();
    encStream.Close();

    byte[] buffer = ms.ToArray();
    ms.Close();

    return buffer;
}

ouptut的前8个字节是我期望的，但其余的我这个代码有什么问题吗？

The first 8 bytes of the ouptut is what I expect but the rest I don't what it is.. is it something wrong with this code?

推荐答案

输入将被填充到下一个块大小使用 PKCS填充。 7字节输入将被填充到8. 8-15到16 16-23到24等等等等。

The input will be padded to the next block size using PKCS padding. 7 bytes input will be padded to 8. 8-15 to 16. 16-23 to 24 and so on and so forth.

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