分而治之的办法进行幂？ [英] divide and conquer approach for exponentiation?

问题描述

由于功课，我应该实行分而治之的大整数幂的方法。我知道Karatsuba的算法乘法，我能学以致用分而治之算法，得到的X ^ Y，无论是大的整数的结果？

As homework, I should implement a divide and conquer approach for exponentiation of big integers. I know Karatsuba's algorithm for multiplication, what divide and conquer algorithm could I apply to get the result of x^y, both being large integers?.

推荐答案

有几个算法的名义下的广场和繁殖。你可以得到一些启发他们。

There are a couple of algorithms grouped together under the name square and multiply. You could get some inspiration from them.

这篇关于分而治之的办法进行幂？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！