使用file_get_contents处理好的错误 [英] Good error handling with file_get_contents
问题描述
我正在使用具有此功能的 simplehtmldom :
I am making use of simplehtmldom which has this funciton:
// get html dom form file
function file_get_html() {
$dom = new simple_html_dom;
$args = func_get_args();
$dom->load(call_user_func_array('file_get_contents', $args), true);
return $dom;
}
我这样使用:
$html3 = file_get_html(urlencode(trim("$link")));
有时,网址可能无效,我想处理这个。我以为我可以使用一个try和catch,但这没有工作,因为它没有抛出异常,它只是给出一个这样的php警告:
Sometimes, a URL may just not be valid and I want to handle this. I thought I could use a try and catch but this hasn't worked since it doesn't throw an exception, it just gives a php warning like this:
[06-Aug-2010 19:59:42] PHP Warning: file_get_contents(http://new.mysite.com/ghs 1/) [<a href='function.file-get-contents'>function.file-get-contents</a>]: failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in /home/example/public_html/other/simple_html_dom.php on line 39
39行是在上面的代码。
Line 39 is in the above code.
如何正确处理这个错误,我可以使用一个简单的如果
条件,它看起来不会返回一个布尔值。
How can i correctly handle this error, can I just use a plain if
condition, it doesn't look like it returns a boolean.
感谢所有的帮助
这是一个很好的解决方案吗?
Is this a good solution?
if(fopen(urlencode(trim("$next_url")), 'r')){
$html3 = file_get_html(urlencode(trim("$next_url")));
}else{
//do other stuff, error_logging
return false;
}
推荐答案
想法:
function fget_contents() {
$args = func_get_args();
// the @ can be removed if you lower error_reporting level
$contents = @call_user_func_array('file_get_contents', $args);
if ($contents === false) {
throw new Exception('Failed to open ' . $file);
} else {
return $contents;
}
}
基本上是 file_get_contents的包装
。它会在失败时抛出异常。
为了避免覆盖 file_get_contents
本身,您可以
Basically a wrapper to file_get_contents
. It will throw an exception on failure.
To avoid having to override file_get_contents
itself, you can
// change this
$dom->load(call_user_func_array('file_get_contents', $args), true);
// to
$dom->load(call_user_func_array('fget_contents', $args), true);
现在您可以:
try {
$html3 = file_get_html(trim("$link"));
} catch (Exception $e) {
// handle error here
}
错误抑制(通过使用 @
或通过降低error_reporting级别是一个有效的解决方案,这可能会导致异常,您可以使用它来处理你的错误。为什么 file_get_contents
可能会产生警告,PHP的手册本身建议降低error_reporting的原因有很多:请参阅手册
Error suppression (either by using @
or by lowering the error_reporting level is a valid solution. This can throw exceptions and you can use that to handle your errors. There are many reasons why file_get_contents
might generate warnings, and PHP's manual itself recommends lowering error_reporting: See manual
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