为什么我不尝试在JSON工作中排除引号？ [英] Why doesn't my attempt to escape quotation marks in JSON work?

问题描述

我正在使用JQuery.parseJSON函数解析JSON字符串，因为我在代码中做了很多次。在这种特殊情况下，我得到：未捕获语法错误：意外的令牌R 。在JSON格式的String中，唯一存在的大写字母R就在转义的引号后面，就是这样的。 ... \R ... 似乎太多的巧合是由这个以外的其他东西造成的，但据我所知，我完全遵循json.org所述的正确语法。

编辑：

我尝试手动删除 \在硬编码测试中，字符串格式完美地转换成一个正确的Javascript对象。换句话说，我的 \绝对是这里的问题...

  var myObject = $ .parseJSON（myString）; 
  

编辑2： strong>

我的String的问题区域在这里显示，无论是工作还是不工作状态，首先是有问题的：

  {lineID：33，boxID：10，title：我的文本与\Ruining Part \ b  

然后工作：

 code> {lineID：33，boxID：10，title：我的文本与破坏部分} 
  

最后我如何将我的javabean对象格式化为JSON字符串。

  String jsonObjectAsString = new Gson （）.toJson（myJavaBeanObject）; 
  

解决方案

你可能需要要转义字符串中的反斜杠，如果它是硬编码的，那么得到解析的最后一个字符串有一个反斜杠，后面跟着一个双引号，否则浏览器会认为你试图逃避你的字符串中的一个双引号，它什么都不做。

所以将你的字符串改为：

  ... \\R ... 
  

I am parsing a JSON-string with the JQuery.parseJSON function, as I have done lot's of times in my code. On this particular case, though, I get: Uncaught SyntaxError: Unexpected token R. The only upper case R that exists, in my JSON-formatted String, comes right after an escaped quotation mark, ... \"R ... like this. It seems like too much of a coincidence to be caused by anything other than this, but as far as I can tell, I have completely followed the proper syntax as described on json.org.

EDIT:

I've tried to manually remove the occurrances of \" in a hardcoded test, and the string formats perfectly into a proper Javascript object. In other words, my \" is definitely the problem here...

var myObject = $.parseJSON(myString);

EDIT 2:

the problematic area of my String is here displayed, both in working, and not working condition. first the problematic one:

{"lineID":33,"boxID":10,"title":"My text with the \"Ruining Part\""}

Then the working one:

{"lineID":33,"boxID":10,"title":"My text with the Ruining Part"}

Finally how i format my javabean object into JSON string.

String jsonObjectAsString = new Gson().toJson(myJavaBeanObject);

解决方案

You probably need to escape the backslash in your string, if it is hardcoded, so that the final string that gets parsed has a single backslash followed by a double quote. Otherwise, the browser thinks you are trying to escape a double quote in your string, which does nothing.

So change your string to:

...\\"R...

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