如何在PHP内部的PHP中编写php？ [英] How to write php within html within php?

问题描述

最近我问过这个问题，而不是直接得到答案，但是我已经明白了如何使用三元运算符来简化代码，将我的html中的if语句替换为变量，我感谢并放置使用 - 但是这也导致其他代码更难阅读，最终没有教会我正确地逃避/解析php在类似于下面的代码。

所以我会喜欢一个简单的显示和告诉如何使以下代码解析，谢谢：

 <？php 
 if （！isset（$ _ POST ['myform']））{
 echo 
 
< form method =POSTaction =<？php if（isset（$ myform_worked）） {echo'somepath';}？>接收字符集= UTF-8 > 
  

这是我试过的，但上面的一行并不解析：

 <？php 
 if（！isset（$ _ POST ['myform']））{
 echo 
 
'< form method =POSTaction ='<？php if（isset（$ myform_worked））{echo'somepath';}？>'accept-charset =UTF- 8&$'
  

我也尝试过（在PHP里面使用双引号：

 <？php if（isset（$ myform_worked））{echo'somepath';}？>
  

请显示这个nub如何做到这一点，谢谢，我不在乎上面的代码是否是BAD ...我只是需要学习如何逃避/解析php里面的html里面php，谢谢。

解决方案

你没有关闭打开的php块工作语法将如下所示：

 <？php 
 // php code 
 ？> 
<！ -  HTML代码 - > 
<？php 
？> 
  

或根据您的问题：

 <？php 
 if（！isset（$ _ POST ['myform']））{
？> 
 
< form method =POSTaction =<？php if（isset（$ myform_worked））{echo'somepath';}？&接收字符集= UTF-8 > 
 
<？php} // if-closing bracket？> 
  

I have recently asked this question, but rather than getting a direct answer, I was shown how to use the ternary operator to simplify my code by substituting if statements inside my html with variables, which I appreciated and put to use - however that also caused other code to be harder to read and ultimately did not teach me to properly escape/parse php in code similar to that below.

So I would love a simple 'show and tell' of how to make the following code parse, thank you:

<?php
if (!isset($_POST['myform'])) {
  echo

<form method="POST" action="<?php if (isset($myform_worked)) { echo 'somepath'; } ?>" accept-charset="UTF-8">

This is what I've tried, but the line above doesn't parse:

<?php
if (!isset($_POST['myform'])) {
  echo

'<form method="POST" action="'<?php if (isset($myform_worked)) { echo 'somepath'; } ?>'" accept-charset="UTF-8">'

I have also tried (using double quotes around the php inside :

"<?php if (isset($myform_worked)) { echo 'somepath'; } ?>"

Please show this nub how to do this, thanks. I do not care if the above code is BAD... I just need to learn how to escape/parse php inside html inside php, thanks.

解决方案

You did not close the open php-block beforehand. The working Syntax would be like this:

<?php
//php code
?>
<!--HTML-Code-->
<?php
?>

Or according to your problem:

<?php
if (!isset($_POST['myform'])) {
?>

<form method="POST" action="<?php if (isset($myform_worked)) { echo 'somepath'; } ?>" accept-charset="UTF-8">

<?php } //if-closing bracket ?>

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