通过元素发生删除的子表（方案） [英] delete sublist by element occurrence (Scheme)

问题描述

我怎么能由它搜索只有一个ELEM删除子列表。

How I could remove a sublist by searching only one elem from it.

例如，让我们的清单：

( (pacific (atlanta ohaio) (NY LI))
  (atlanta (pacific blue) (ohaio green)) )

和我想从列表中删除和平，并获得：

And I want to remove "pacific" from the list and to get:

( (pacific (atlanta ohaio) (NY LI))
  (atlanta (ohaio green)) )

任何想法将大大AP preciated：）

Any ideas would be greatly appreciated :).

推荐答案

该标准从输入列表中删除一个元素没说清楚的问题。这适用于所示的例子：

The criteria for deleting an element from the input list is not stated clearly in the question. This will work for the example shown:

(define lst
  '((pacific (atlanta ohaio) (NY LI))
    (atlanta (pacific blue) (ohaio green))))

(map (lambda (slst)
       (filter (lambda (e)
                 (not (and (list? e) (member 'pacific e))))
               slst))
     lst)

=> '((pacific (atlanta ohaio) (NY LI)) (atlanta (ohaio green)))

如果有必要，对于其他输入，可直到结果是根据需要调整状态，在最里面的lambda。举例来说，我跨preTED在问题的注释：

If necessary, for other inputs you can tweak the condition in the innermost lambda until the result is as desired. For instance, I interpreted the comment in the question:

我要删除包含搜索词的子表

I want to delete the sublist that contains the searched word

为：找到搜索词中的的任何位置的一个子表内;如果所搜索的单词，可以发现在，比方说，只有第一位置，然后相应地调整条件

As: "find the searched word in any position inside a sublist"; if the searched word can be found in, say, only the first position then adjust the condition accordingly.

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